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ICSE Class 10 Chemistry: Mole Concept — Complete Notes 2026

T

Tushar Parik

Author

2 min read

ICSE Class 10 Chemistry: Mole Concept — Complete Notes 2026

This comprehensive guide from Bright Tutorials covers everything you need to know — with clear explanations, exam tips, and key points for board exam preparation.

In This Article

  1. The Mole — Definition and Significance
  2. Molar Volume of Gases
  3. Percentage Composition
  4. Empirical and Molecular Formula
  5. Stoichiometry and Mole Ratios
  6. Limiting Reagent and Percentage Yield
  7. Numericals — Mole Concept

The Mole — Definition and Significance

  • 1 mole = 6.022 × 10²³ particles (Avogadro's number N_A)
  • Molar mass = mass of 1 mole of substance in grams (numerically equal to relative molecular mass)
  • Mole bridges atomic-scale chemistry with measurable laboratory quantities

Molar Volume of Gases

  • At STP (0°C, 1 atm): 1 mole of any gas occupies 22.4 L
  • At RTP (25°C, 1 atm): 1 mole occupies ~24 L
  • Application: convert volume of gas at STP to moles: n = V/22.4

Percentage Composition

  • % element = (mass of element in formula / molar mass) × 100
  • Example: % C in CO₂ = (12/44) × 100 = 27.3%
  • Used to verify formula and check purity of compound

Empirical and Molecular Formula

  • Empirical formula: simplest whole-number ratio of atoms
  • Molecular formula = n × empirical formula; n = Mr/empirical formula mass
  • Step-by-step: % → moles → divide by smallest → whole number ratio

Stoichiometry and Mole Ratios

  • Balanced equation gives mole ratio of reactants and products
  • Mole-to-mole: N₂ + 3H₂ → 2NH₃; 1:3:2 mole ratio
  • Mole-to-mass and mass-to-mass conversions using molar masses

Limiting Reagent and Percentage Yield

  • Limiting reagent is fully consumed first; determines maximum product
  • Find moles of each reactant, divide by stoichiometric coefficient — smallest is limiting
  • % yield = (actual yield / theoretical yield) × 100%

Numericals — Mole Concept

  • Find moles and molecules in 36 g of water
  • Calculate mass of NaCl produced from 5 g of Na with excess Cl₂
  • Determine empirical formula given: C=40%, H=6.67%, O=53.33%

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