ICSE Class 10 Chemistry: Mole Concept — Complete Notes 2026
Tushar Parik
Author
ICSE Class 10 Chemistry: Mole Concept — Complete Notes 2026
This comprehensive guide from Bright Tutorials covers everything you need to know — with clear explanations, exam tips, and key points for board exam preparation.
In This Article
The Mole — Definition and Significance
- 1 mole = 6.022 × 10²³ particles (Avogadro's number N_A)
- Molar mass = mass of 1 mole of substance in grams (numerically equal to relative molecular mass)
- Mole bridges atomic-scale chemistry with measurable laboratory quantities
Molar Volume of Gases
- At STP (0°C, 1 atm): 1 mole of any gas occupies 22.4 L
- At RTP (25°C, 1 atm): 1 mole occupies ~24 L
- Application: convert volume of gas at STP to moles: n = V/22.4
Percentage Composition
- % element = (mass of element in formula / molar mass) × 100
- Example: % C in CO₂ = (12/44) × 100 = 27.3%
- Used to verify formula and check purity of compound
Empirical and Molecular Formula
- Empirical formula: simplest whole-number ratio of atoms
- Molecular formula = n × empirical formula; n = Mr/empirical formula mass
- Step-by-step: % → moles → divide by smallest → whole number ratio
Stoichiometry and Mole Ratios
- Balanced equation gives mole ratio of reactants and products
- Mole-to-mole: N₂ + 3H₂ → 2NH₃; 1:3:2 mole ratio
- Mole-to-mass and mass-to-mass conversions using molar masses
Limiting Reagent and Percentage Yield
- Limiting reagent is fully consumed first; determines maximum product
- Find moles of each reactant, divide by stoichiometric coefficient — smallest is limiting
- % yield = (actual yield / theoretical yield) × 100%
Numericals — Mole Concept
- Find moles and molecules in 36 g of water
- Calculate mass of NaCl produced from 5 g of Na with excess Cl₂
- Determine empirical formula given: C=40%, H=6.67%, O=53.33%
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