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ICSE Class 10 Maths: Compound Interest — Formulas & Notes 2026

T

Tushar Parik

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2 min read

ICSE Class 10 Maths: Compound Interest — Formulas & Notes 2026

This comprehensive guide from Bright Tutorials covers everything you need to know — with clear explanations, exam tips, and key points for board exam preparation.

In This Article

  1. Simple Interest vs. Compound Interest
  2. Compound Interest Formula
  3. Compounding Frequency
  4. Depreciation
  5. Population Growth Problems
  6. Instalment Problems
  7. ICSE Numericals — Compound Interest

Simple Interest vs. Compound Interest

  • SI = PRT/100; interest calculated on original principal only
  • CI: interest added to principal each period; next period's interest calculated on new amount
  • CI > SI for same P, R, T when T > 1 year

Compound Interest Formula

  • A = P(1 + R/100)ⁿ where A = amount, P = principal, R = rate per period, n = number of periods
  • CI = A − P
  • Finding P when A, R, n given: P = A / (1 + R/100)ⁿ

Compounding Frequency

  • Annual: n = years, R = annual rate
  • Half-yearly: n = 2 × years, R = annual rate/2
  • Quarterly: n = 4 × years, R = annual rate/4

Depreciation

  • Value decreases each year: A = P(1 − R/100)ⁿ (depreciation formula)
  • Applications: car price, machine value, population decline
  • ICSE: find value after n years; find original cost given depreciated value

Population Growth Problems

  • A = P(1 + R/100)ⁿ for constant percentage growth
  • Find population after n years; find rate given initial and final population
  • Combined growth and decline: A = P(1 + R₁/100)(1 − R₂/100)

Instalment Problems

  • Equal periodic payments; ICSE uses 2–3 instalment problems
  • Method: equate total amount paid (with interest) to total cash price
  • Find instalment amount given cash price, interest rate and number of instalments

ICSE Numericals — Compound Interest

  • ₹5000 at 10% p.a. compounded half-yearly for 1.5 years — find CI
  • A car depreciates at 15% annually; original cost ₹4,00,000 — value after 3 years
  • Find P if A=₹12,100, R=10% p.a., n=2 years

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