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CBSE Class 10 Science Question 31 of 41

Electricity — Question 2

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Question 2

Redraw the circuit of Question 1, putting in an ammeter to measure the current through the resistors and a voltmeter to measure the potential difference across the 12 Ω resistor. What would be the readings in the ammeter and the voltmeter?

Answer
Redraw the circuit of Question 1, putting in an ammeter to measure the current through the resistors and a voltmeter to measure the potential difference across the 12 Ω resistor. What would be the readings in the ammeter and the voltmeter? NCERT Class 10 Science CBSE Solutions.

According to Ohm's Law,

V = IR

The total resistance of the circuit is 5 Ω + 8 Ω + 12 Ω = 25 Ω.

Potential difference (V) = 6 V,

I = VR=625\dfrac{\text{V}}{\text{R}} = \dfrac{6}{25} = 0.24 A

Hence, current shown in ammeter = 0.24 A

Let potential difference across the 12 Ω resistor be V1.

V1 = 0.24 × 12 = 2.88 V

Therefore, the voltmeter reading will be 2.88 V.