Question 1

Question 11Select from the following the correct statement about tropic movement in plants:It is due to stimulus of touch and temperature.It does not depend upon the direction of stimulus received.It is observed only in roots and not in stems.It is a growth related movement.

Accepted Answer

It is a growth related movement.Reason — Tropic movement in plants is related to growth. It occurs in stem as well as roots. It is affected by touch, gravitation and light.

Question 2

Question 12Select the INCORRECT match (between the plant and its vegetative part) from the following :Bryophyllum, leafPotato, stemMoney-plant, stemRose, root

Accepted Answer

Rose, rootReason— Rose is propagated by stem.

Source: This question is from Solved 2023 Question Paper CBSE Class 10 Science, Science &mdash; Class 10, CBSE Board.
Key Concepts CoveredThis question tests your understanding of the following concepts from the chapter Solved 2023 Question Paper CBSE Class 10 Science: Question, Select, Incorrect, Match, Plant, Vegetative. These are fundamental topics in Science that students are expected to master as part of the CBSE Class 10 curriculum.A thorough understanding of these concepts will help you answer similar questions confidently in your CBSE examinations. These topics are frequently tested in both objective and subjective sections of Science papers. We recommend revising the relevant section of your textbook alongside practising these solved examples to build a strong foundation.
How to Approach This QuestionRead the question carefully and identify what is being asked. Break down complex questions into smaller parts. Use the terminology and concepts discussed in this chapter. Structure your answer logically — begin with a definition or key statement, then provide supporting details. Review your answer to ensure it addresses all parts of the question completely.
Key Points to RememberRead the question carefully and identify all parts before answering.
Use the terminology specific to this subject and chapter.
Review the textbook content for this chapter before attempting questions.
Practice writing concise, well-structured answers within time limits.
Related Questions from Solved 2023 Question Paper CBSE Class 10 ScienceQ1: Question 34(a) A saturated organic compound &#x27;A&#x27; belongs to the homologous series of alcohols. On...
Q10: Question 33(b) (i) Construct a food chain of four trophic levels comprising the following : Hawk,...
Q11: Question 11 Select from the following the correct statement about tropic movement in plants: It is...
Q13: Question 13 If four identical resistors, of resistance 8 ohm, are first connected in series so as...
Q14: Question 14 In domestic electric circuits the wiring with 15 A current rating is for the electric...
Practice more questions from Solved 2023 Question Paper CBSE Class 10 Science &mdash; Science, Class 10 CBSE

Question 3

Question 13If four identical resistors, of resistance 8 ohm, are first connected in series so as to give an effective resistance Rs, and then connected in parallel so as to give an effective resistance Rp then the ratio RsRp\dfrac{R_s}{R_p}Rp​Rs​​ is3220.516

Accepted Answer

16Reason — Four identical resistors of resistance 8 Ω are connected in series :So, Rs = 8+8+8+8 = 32 ΩWhen connected in parallel:1Rp\dfrac{1}{R_p}Rp​1​ = 18\dfrac{1}{8}81​ + 18\dfrac{1}{8}81​ + 18\dfrac{1}{8}81​ + 18\dfrac{1}{8}81​1Rp\dfrac{1}{R_p}Rp​1​ = 1+1+1+18\dfrac{1+1+1+1}{8}81+1+1+1​ = 48\dfrac{4}{8}84​ = 12\dfrac{1}{2}21​So, Rp = 2 ΩRsRp\dfrac{R_s}{R_p}Rp​Rs​​ = 322\dfrac{32}{2}232​ = 16

Question 4

Question 14In domestic electric circuits the wiring with 15 A current rating is for the electric devices which havehigher power ratings such as geyser.lower power ratings such as fan.metallic bodies and low power ratings.non-metallic bodies and low power ratings.

Accepted Answer

higher power ratings such as geyser.Reason — As P = i2RHence, in domestic electric circuits the wiring with 15 A current rating is for the electric devices which have higher power ratings such as geyser.

Question 5

Question 15In the following diagram, the position of the needle is shown on the scale of a voltmeter. The least count of the voltmeter and the reading shown by it respectively are :0.15 V and 1.6 V0.05 V and 1.6 V0.15 V and 1.8 V0.05 V and 1.8 V

Accepted Answer

0.15 V and 1.8 VReason — Least count of any scale is the value measured by a single division on it.10 div = 1.5 VSo, 1 div = 1.510\dfrac{1.5}{10}101.5​ = 0.15 VHence, least count = 0.15 VReading shown = least count x no. of div. = 0.15 x 12 = 1.8 VHence, Reading shown = 1.8 V

Question 6

Question 16The resultant magnetic field at point 'P' situated midway between two parallel wires (placed horizontally) each carrying a steady current I isin the same direction as the current in the wires.in the vertically upward direction.zeroin the vertically downward direction.

Accepted Answer

zeroReason — The magnetic fields produced at the midpoint P, by the currents flowing in the same direction in the two parallel wires will be equal in magnitude but opposite in direction.Hence, the resultant magnetic field at P will be zero.

Question 7

Question 17Assertion (A) : The colour of aqueous solution of copper sulphate turns colourless when a piece of lead is added to it.Reason (R) : Lead is more reactive than copper, and hence displaces copper from its salt solution.Both (A) and (R) are true and (R) is the correct explanation of (A).Both (A) and (R) are true, but (R) is not the correct explanation of (A).(A) is true, but (R) is false.(A) is false, but (R) is true.

Accepted Answer

Both (A) and (R) are true and (R) is the correct explanation of (A)Reason — When a piece of lead is added to an aqueous solution of copper sulphate, a displacement reaction takes place as lead is more reactive than copper hence lead displaces copper from the copper sulphate solution. The chemical equation for the reaction is:Pb + CuSO4 ⟶ PbSO4 + CuThis results in a colorless solution [PbSO4].

Question 8

Question 18Assertion (A) : Genes inherited from the parents decide the sex of a child.Reason (R) : X chromosome in a male child is inherited from his father.Both (A) and (R) are true and (R) is the correct explanation of (A).Both (A) and (R) are true, but (R) is not the correct explanation of (A).(A) is true, but (R) is false.(A) is false, but (R) is true.

Accepted Answer

(A) is true, but (R) 1s false.Reason — Sex of a child is decided by the chromosome (X or Y) of father that is inherited by the embryo. Genes on chromosome Y are responsible for male child.

Question 9

Question 19Assertion (A) : Blood clotting prevents excessive loss of blood.Reason (R) : Blood clotting is due to blood plasma and white blood cells present in the blood.Both (A) and (R) are true and (R) is the correct explanation of (A).Both (A) and (R) are true, but (R) is not the correct explanation of (A).(A) is true, but (R) is false.(A) is false, but (R) is true.

Accepted Answer

(A) is true, but (R) is false.Reason — Blood clotting is due to blood platelets, fibrinogen and Prothrombin.

Source: This question is from Solved 2023 Question Paper CBSE Class 10 Science, Science &mdash; Class 10, CBSE Board.
Key Concepts CoveredThis question tests your understanding of the following concepts from the chapter Solved 2023 Question Paper CBSE Class 10 Science: Question, Assertion, Blood, Clotting, Prevents, Excessive. These are fundamental topics in Science that students are expected to master as part of the CBSE Class 10 curriculum.A thorough understanding of these concepts will help you answer similar questions confidently in your CBSE examinations. These topics are frequently tested in both objective and subjective sections of Science papers. We recommend revising the relevant section of your textbook alongside practising these solved examples to build a strong foundation.
How to Approach This QuestionRead the question carefully and identify what is being asked. Break down complex questions into smaller parts. Use the terminology and concepts discussed in this chapter. Structure your answer logically — begin with a definition or key statement, then provide supporting details. Review your answer to ensure it addresses all parts of the question completely.
Key Points to RememberRead the question carefully and identify all parts before answering.
Use the terminology specific to this subject and chapter.
Review the textbook content for this chapter before attempting questions.
Practice writing concise, well-structured answers within time limits.
Related Questions from Solved 2023 Question Paper CBSE Class 10 ScienceQ1: Question 34(a) A saturated organic compound &#x27;A&#x27; belongs to the homologous series of alcohols. On...
Q10: Question 33(b) (i) Construct a food chain of four trophic levels comprising the following : Hawk,...
Q11: Question 11 Select from the following the correct statement about tropic movement in plants: It is...
Q13: Question 13 If four identical resistors, of resistance 8 ohm, are first connected in series so as...
Q14: Question 14 In domestic electric circuits the wiring with 15 A current rating is for the electric...
Practice more questions from Solved 2023 Question Paper CBSE Class 10 Science &mdash; Science, Class 10 CBSE

Question 10

Question 20Assertion (A) : The strength of the magnetic field produced at the centre of a current carrying circular coil increases on increasing the number of turns in it.Reason (R) : The current in each circular turn has the same direction and the magnetic field due to each turn then just adds up.Both (A) and (R) are true and (R) is the correct explanation of (A).Both (A) and (R) are true, but (R) is not the correct explanation of (A).(A) is true, but (R) is false.(A) is false, but (R) is true.

Accepted Answer

Both (A) and (R) are true and (R) is the correct explanation of (A).Reason — Magnetic field strength is directly proportional to the number of turns of the circular coil. Hence, strength of the magnetic field increases on increasing the number of turns in it because current in each circular turn has the same direction and the magnetic field due to each turn then just adds up.

Question 11

Question 21(b)Write balanced chemical equation for the reaction that occurs when :(i) blue coloured copper sulphate crystals are heated and(ii) Sodium hydrogen carbonate is heated during cooking.

Accepted Answer

(i) When blue coloured copper sulphate crystals are heated :CuSO4.5H2O →Δ\xrightarrow{\Delta}Δ​ CuSO4 + 5H2O(ii) When sodium hydrogen carbonate is heated during cooking2NaHCO3 →Δ\xrightarrow{\Delta}Δ​ Na2CO3 (s) + H2O (l) + CO2 (↑)

Question 12

Question 24Name the part of the human excretory system where nephrons are found. Write the structure and function of nephrons.

Accepted Answer

The part of the human excretory system where nephrons are found are Kidneys.Structure of Nephron — Nephron is the basic filtration unit in the kidney. It consists of a tubule which is connected with a collecting duct at one end and a cup shaped structure at the other end, called Bowman's capsule. Every Bowman's capsule contains a cluster of capillaries called glomerulus within the cup-shaped structure.Function of Nephron — The blood enters into glomerulus through afferent arteriole of renal artery and leaves it through efferent arteriole. This causes filtration of the blood. Then the filtrate passes into the tubular part of the nephron. Here, useful substances such as glucose, amino acids, salts and some water are re-absorbed into the blood by the capillaries surrounding the nephron tubule. The filtrate which remains after the re-absorption is called the urine, which is collected from nephron by the collecting duct to carry it to the urinary bladder and then to the urethra.

Question 13

Question 25(a)A narrow beam XY of white light is passing through a glass prism ABC as shown in the diagram :Trace it on your answer sheet and show the path of the emergent beam as observed on the screen PQ.Name the phenomenon observed and state its cause.

Accepted Answer

The path of the emergent beam is shown in the diagram below:The phenomenon of the splitting up of the white light into its constituent colours is called dispersion of light.The cause of dispersion of white light is the change in speed of light with wavelength.When white light enters the first surface of a prism, light of different colours due to their different speeds in glass, get deviated through different angles towards the base of the prism. On the second surface of prism, only refraction takes place (from glass to air) and different colours are deviated through different angles. As a result, colours get further separated on refraction at the second surface.

Question 14

Question 30(a) Complete the following ray diagram to show the formation of image :(b) Mention the nature, position and size of the image formed in this case.(c) State the sign of the image distance in this case using the Cartesian sign convention.

Accepted Answer

(a) The completed ray diagram showing the formation of image is given below:(b) The image formed is virtual, erect, diminished and located behind the mirror between P and F.(c) positive

Question 15

Question 32(b)(i) Draw the pattern of magnetic field lines of(1) a current carrying solenoid(2) a bar magnet(ii) List two distinguishing features between the two fields.

Accepted Answer

(i)(1) The pattern of magnetic field lines of a current carrying solenoid is shown below:(2) The pattern of magnetic field lines of a bar magnet is shown below:(ii) Distinguishing features between :Magnetic field lines of a current carrying solenoidMagnetic field lines of a bar magnetIf we cut a solenoid into two halves, the magnetic field strength of the halves gets decreased.When we cut a bar magnet into two halves, the magnetic properties do not change and both act as a magnet.The poles of a solenoid can be altered and hence the direction of magnetic field lines.In case of a bar magnet, it is fixed.

Question 16

Question 33(a)(i) Why does a kitchen garden called an artificial ecosystem while a forest is considered to be a natural ecosystem ?(ii) While designing an artificial ecosystem at home, write any two things to be kept in mind to convert it into a self-sustaining system. Give reason to justify your answer.

Accepted Answer

(i) Kitchen garden is known as artificial ecosystem because the biotic and abiotic factors are modified by humans and not decided by the nature as in natural ecosystems like forest. In forests, humans do not modify biotic or abiotic factors.(ii) Two things to be kept in mind to convert an artificial ecosystem into a self-sustaining system are:Balance between producers and consumers — We should select inter-dependable producers and consumer to make the ecosystem self sustainable. They should form food web so that their population is controlled.Waste management — The involvement of decomposers is very important for sustainable ecosystem.Natural ecosystems are self sustaining due to a perfect relation of interdependence. For converting an artificial ecosystem into a self-sustaining system we should try to minimize human interference and include organisms that make it sustainable.

Question 17

Question 33(b)(i) Construct a food chain of four trophic levels comprising the following :Hawk, snake, plants, rat.(ii) 20,000 J of energy was transferred by the producers to the organism of second trophic level. Calculate the amount of energy that will be transferred by organisms of the third trophic level to the organisms of the fourth trophic level.

Accepted Answer

(i) Plants → Rat → Snake → Hawk(ii) According to the 10% rule of energy transfer, 10% of energy is transferred to next trophic level. Amount of energy available to second trophic level = 20,000 J Therefore, amount of energy transferred to third trophic level = 10% of 20,000 J = 2000 J. And, amount of energy transferred to fourth trophic level = 10% of 2000 J = 200 J

Question 18

Question 34(a)A saturated organic compound 'A' belongs to the homologous series of alcohols.On heating 'A' with concentrated sulphuric acid at 443 K, it forms an unsaturated compound 'B' with molecular mass 28 u.The compound 'B' on addition of one mole of hydrogen in the presence of Nickel, changes to a saturated hydrocarbon 'C'.(i) Identify A, B and C.(ii) Write the chemical equations showing the conversion of A into B.(iii) What happens when compound C undergoes combustion ?(iv) State one industrial application of hydrogenation reaction.(v) Name the products formed when compound A reacts with sodium.

Accepted Answer

(i) Compounds A, B and C are:A → EthanolB → EtheneC → EthaneC2H5OH→Conc. sulphuric acid{\xrightarrow{	ext{Conc. sulphuric acid}}}Conc. sulphuric acid​ CH2=CH2CH2=CH2 + H2 →Ni{\xrightarrow{	ext{Ni}}}Ni​ CH3-CH3(ii) C2H5OH→Conc. sulphuric acid{\xrightarrow{	ext{Conc. sulphuric acid}}}Conc. sulphuric acid​ CH2=CH2(iii) When ethane undergoes combustion, carbon dioxide is produced along with water and heat.2C2H6 + 7O2 ⟶ 4CO2 + 6H2O + Heat(iv) In industry, hydrogenation reaction is used for preparing vegetable ghee from vegetable oils(v) Sodium ethoxide and Hydrogen2Na + 2C2H5OH ⟶ 2C2H5ONa + H2

Question 19

Question 36(a) An electric iron consumes energy at a rate of 880 W when heating is at the maximum rate and 330 W when the heating is at the minimum. If the source voltage is 220 V, calculate the current and resistance in each case.(b) What is heating effect of electric current ?(c) Find an expression for the amount of heat produced when a current passes through a resistor for some time.

Accepted Answer

(a) Given,Power (P) = 880 W [when heating is at the maximum rate ]Power (P) = 330 W [when heating is at the minimum rate ]Voltage (V) = 220 VCase I : When heating is at the maximum rateWe know,P = VISubstituting we get,880 = 220 x II = 880220\dfrac{880}{220}220880​ = 4 AFrom V = IRSubstituting we get,220 = 4 x RR = 2204\dfrac{220}{4}4220​ = 55 ΩHence, when heating is at the maximum rate, I = 4 A and R = 55 ΩCase II : When heating is at the minimum rateSubstituting we get current (I)330 = 220 x II = 330220\dfrac{330}{220}220330​ = 32\dfrac{3}{2}23​ = 1.5 ASubstituting we get resistance (R),220 = 1.5 x RR = 2201.5\dfrac{220}{1.5}1.5220​ = 1.46 ΩHence, when heating is at the minimum rate, I = 1.5 A and R = 1.46 Ω(b) When the electric circuit is purely resistive, that is, a configuration of resistors only connected to a battery; the source energy continually gets dissipated entirely in the form of heat. This is called heating effect of electric current.(c) H = I2Rt whereThis is known as Joule's law of heating.

Question 20

Question 39Hold a concave mirror in your hand and direct its reflecting surface towards the sun. Direct the light reflected by the mirror on to a white card-board held close to the mirror. Move the card-board back and forth gradually until you find a bright, sharp spot of light on the board. This spot of light is the image of the sun on the sheet of paper; which is also termed as 'Principal Focus' of the concave mirror.(a) List two applications of concave mirror.(b) If the distance between the mirror and the principal focus is 15 cm, find the radius of curvature of the mirror.(c) Draw a ray diagram to show the type of image formed when an object is placed between pole and focus of a concave mirror.OR(c) An object 10 cm in size is placed at 100 cm in front of a concave mirror. If its image is formed at the same point where the object is located, find :(i) focal length of the mirror, and(ii) magnification of the image formed with sign as per Cartesian sign convention.

Accepted Answer

(a) Two applications of concave mirror are :As a reflector — They are used in torches and vehicle headlights to get a powerful parallel beam of light.As a shaving mirror — When a concave mirror is held near the face (such that the face is between pole and focus of the mirror), it gives an upright and magnified image. Hence even tiny hair can be seen.(b) As we know, R = 2f where, R is the radius of curvature and f is the focal length.Given focal length (f) = 15 cmSo, substituting we get,R = 2 x 15 = 30 cm(c) Ray diagram showing the type of image formed when an object is placed between pole and focus of a concave mirror is given below:OR(c) Given,Object distance (u) = -100 cmImage distance (v) = -100 cmFocal length (f) = ?[f in case of a concave mirror is negative.]Using formula,1f\dfrac{1}{	ext{f}}f1​ = 1v\dfrac{1}{	ext{v}}v1​ + 1u\dfrac{1}{	ext{u}}u1​We get,1f\dfrac{1}{	ext{f}}f1​ = 1-100\dfrac{1}{	ext{-100}}-1001​ + 1-100\dfrac{1}{	ext{-100}}-1001​1f\dfrac{1}{	ext{f}}f1​ = 2-100\dfrac{2}{	ext{-100}}-1002​ = 1-50\dfrac{1}{	ext{-50}}-501​So, f = -50 cmHence, focal length = -50 cm.(ii) Size of object (ho) = 10 cmmagnification = ?From formula,m = - vu\dfrac{	ext{v}}{	ext{u}}uv​Substituting we get,m = - −100−100\dfrac{-100}{-100}−100−100​ = -1Hence, magnification of the object = -1 i.e., inverted image is formed of same size as object.

Solved 2023 Question Paper CBSE Class 10 Science

Section A (Objective Type Questions 1 Mark Each)

Section B (Very Short Answer Questions 2 Marks Each)

Section C (Short Answer Questions 3 Marks Each)

Section D (Long Answer Questions 5 Marks Each)

Section E (Source/Case Based Questions 4 Marks Each)