Question 1

Question 9Receptors are usually located in sense organs. Gustatory receptors are present intonguenoseeyeear

Accepted Answer

tongueReason — Gustatory receptors are present in taste buds of tongue. They perceive taste of food.

Source: This question is from Solved 2024 Sample Question Paper CBSE Class 10 Science, Science &mdash; Class 10, CBSE Board.
Key Concepts CoveredThis question tests your understanding of the following concepts from the chapter Solved 2024 Sample Question Paper CBSE Class 10 Science: Question, Receptors, Located, Sense, Organs, Gustatory. These are fundamental topics in Science that students are expected to master as part of the CBSE Class 10 curriculum.A thorough understanding of these concepts will help you answer similar questions confidently in your CBSE examinations. These topics are frequently tested in both objective and subjective sections of Science papers. We recommend revising the relevant section of your textbook alongside practising these solved examples to build a strong foundation.
How to Approach This QuestionRead the question carefully and identify what is being asked. Break down complex questions into smaller parts. Use the terminology and concepts discussed in this chapter. Structure your answer logically — begin with a definition or key statement, then provide supporting details. Review your answer to ensure it addresses all parts of the question completely.
Key Points to RememberRead the question carefully and identify all parts before answering.
Use the terminology specific to this subject and chapter.
Review the textbook content for this chapter before attempting questions.
Practice writing concise, well-structured answers within time limits.
Related Questions from Solved 2024 Sample Question Paper CBSE Class 10 ScienceQ1: Question 37 The table given below shows the hints given by the quiz master in a quiz. S. No. HINT...
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Q12: Question 12 A sportsman, after a long break of his routine exercise, suffered muscular cramps...
Q13: Question 13 An object is placed in front of a convex mirror. Its image is formed : at a distance...
Q14: Question 14 When light enters the atmosphere it strikes on extremely fine particles, which deflect...
Practice more questions from Solved 2024 Sample Question Paper CBSE Class 10 Science &mdash; Science, Class 10 CBSE

Question 2

Question 10A farmer wants to grow banana plants genetically similar enough to the plants already available in his field. Which one of the following methods would you suggest for this purpose?RegenerationBuddingVegetative propagationSexual reproduction

Accepted Answer

Vegetative propagationReason — Banana is reproduced by vegetative method (rhizomes). Resulting plants are identical to mother plant.

Source: This question is from Solved 2024 Sample Question Paper CBSE Class 10 Science, Science &mdash; Class 10, CBSE Board.
Key Concepts CoveredThis question tests your understanding of the following concepts from the chapter Solved 2024 Sample Question Paper CBSE Class 10 Science: Question, Farmer, Wants, Grow, Banana, Plants. These are fundamental topics in Science that students are expected to master as part of the CBSE Class 10 curriculum.A thorough understanding of these concepts will help you answer similar questions confidently in your CBSE examinations. These topics are frequently tested in both objective and subjective sections of Science papers. We recommend revising the relevant section of your textbook alongside practising these solved examples to build a strong foundation.
How to Approach This QuestionRead the question carefully and identify what is being asked. Break down complex questions into smaller parts. Use the terminology and concepts discussed in this chapter. Structure your answer logically — begin with a definition or key statement, then provide supporting details. Review your answer to ensure it addresses all parts of the question completely.
Key Points to RememberRead the question carefully and identify all parts before answering.
Use the terminology specific to this subject and chapter.
Review the textbook content for this chapter before attempting questions.
Practice writing concise, well-structured answers within time limits.
Related Questions from Solved 2024 Sample Question Paper CBSE Class 10 ScienceQ1: Question 37 The table given below shows the hints given by the quiz master in a quiz. S. No. HINT...
Q11: Question 11 Height of a plant is regulated by: DNA which is directly influenced by growth hormone....
Q12: Question 12 A sportsman, after a long break of his routine exercise, suffered muscular cramps...
Q13: Question 13 An object is placed in front of a convex mirror. Its image is formed : at a distance...
Q14: Question 14 When light enters the atmosphere it strikes on extremely fine particles, which deflect...
Practice more questions from Solved 2024 Sample Question Paper CBSE Class 10 Science &mdash; Science, Class 10 CBSE

Question 3

Question 11Height of a plant is regulated by:DNA which is directly influenced by growth hormone.Genes which regulate the proteins directly.Growth hormones under the influence of the enzymes coded by a gene.Growth hormones directly under the influence of a gene.

Accepted Answer

Growth hormones under the influence of the enzymes coded by a gene.Reason — Genes code for enzymes that influence the synthesis and regulation of growth hormones, ultimately determining the plant's overall growth and height.

Question 4

Question 12A sportsman, after a long break of his routine exercise, suffered muscular cramps during a heavy exercise session. This happened due to:lack of carbon dioxide and formation of pyruvate.presence of oxygen and formation of ethanol.lack of oxygen and formation of lactic acid.lack of oxygen and formation of carbon dioxide.

Accepted Answer

lack of oxygen and formation of lactic acid.Reason — Muscular cramps during heavy exercise are often associated with the accumulation of lactic acid in muscles. This occurs when there is insufficient oxygen available to meet the energy demands of the muscles, leading to anaerobic metabolism and the production of lactic acid.

Question 5

Question 13An object is placed in front of a convex mirror. Its image is formed :at a distance equal to the object distance in front of the mirror.at twice the distance of the object in front of the mirror.half the distance of the object in front of the mirror.behind the mirror and it's position varies according to the object distance.

Accepted Answer

behind the mirror and it's position varies according to the object distance.Reason — When an object is placed in front of a convex mirror, its image is formed behind the mirror and it's position varies according to the object distance.

Question 6

Question 14When light enters the atmosphere it strikes on extremely fine particles, which deflect the rays of light in all possible directions, This is due to -reflection of lightatmospheric refractionscattering of lightdispersion of light

Accepted Answer

scattering of lightReason — When light enters the atmosphere it strikes on extremely fine particles, which deflect the rays of light in all possible directions, This is due to scattering of light.

Question 7

Question 15In 1987, an agreement was formulated by the United Nations Environment Programme (UNEP) to freeze the production of “X” to prevent depletion of “Y”. “X” and “Y” respectively referred here are:Ozone; CFCsCFCs; rays UVCFCs; OzoneUV rays; Diatomic oxygen

Accepted Answer

CFCs, OzoneReason — In 1987, an agreement was formulated by the United Nations Environment Programme (UNEP) to freeze the production of CFCs to prevent the depletion of Ozone.

Question 8

Question 16Which of the following features relates to biodegradable substances?Broken down by biological processesRemain inertPersist in environment for long timeMay harm the ecosystem

Accepted Answer

Broken down by biological processesReason — Biodegradable substances are the substance that degrade or decompose naturally by the action of microorganisms.

Source: This question is from Solved 2024 Sample Question Paper CBSE Class 10 Science, Science &mdash; Class 10, CBSE Board.
Key Concepts CoveredThis question tests your understanding of the following concepts from the chapter Solved 2024 Sample Question Paper CBSE Class 10 Science: Question, Relates, Biodegradable, Substances, Broken, Down. These are fundamental topics in Science that students are expected to master as part of the CBSE Class 10 curriculum.A thorough understanding of these concepts will help you answer similar questions confidently in your CBSE examinations. These topics are frequently tested in both objective and subjective sections of Science papers. We recommend revising the relevant section of your textbook alongside practising these solved examples to build a strong foundation.
How to Approach This QuestionRead the question carefully and identify what is being asked. Break down complex questions into smaller parts. Use the terminology and concepts discussed in this chapter. Structure your answer logically — begin with a definition or key statement, then provide supporting details. Review your answer to ensure it addresses all parts of the question completely.
Key Points to RememberRead the question carefully and identify all parts before answering.
Use the terminology specific to this subject and chapter.
Review the textbook content for this chapter before attempting questions.
Practice writing concise, well-structured answers within time limits.
Related Questions from Solved 2024 Sample Question Paper CBSE Class 10 ScienceQ1: Question 37 The table given below shows the hints given by the quiz master in a quiz. S. No. HINT...
Q11: Question 11 Height of a plant is regulated by: DNA which is directly influenced by growth hormone....
Q12: Question 12 A sportsman, after a long break of his routine exercise, suffered muscular cramps...
Q13: Question 13 An object is placed in front of a convex mirror. Its image is formed : at a distance...
Q14: Question 14 When light enters the atmosphere it strikes on extremely fine particles, which deflect...
Practice more questions from Solved 2024 Sample Question Paper CBSE Class 10 Science &mdash; Science, Class 10 CBSE

Question 9

Question 17Assertion: Rusting of Iron is endothermic in nature.Reason: As the reaction is slow, the release of heat is barely evident.Both A and R are true, and R is the correct explanation of A.Both A and R are true, and R is not the correct explanation of A.A is true but R is false.A is false but R is true.

Accepted Answer

A is false but R is trueReason — Rusting of iron is an exothermic process. It is a slow process and the amount of heat released isn't significant per unit of time.

Source: This question is from Solved 2024 Sample Question Paper CBSE Class 10 Science, Science &mdash; Class 10, CBSE Board.
Key Concepts CoveredThis question tests your understanding of the following concepts from the chapter Solved 2024 Sample Question Paper CBSE Class 10 Science: Question, Assertion, Rusting, Iron, Endothermic, Nature. These are fundamental topics in Science that students are expected to master as part of the CBSE Class 10 curriculum.A thorough understanding of these concepts will help you answer similar questions confidently in your CBSE examinations. These topics are frequently tested in both objective and subjective sections of Science papers. We recommend revising the relevant section of your textbook alongside practising these solved examples to build a strong foundation.
How to Approach This QuestionRead the question carefully and identify what is being asked. Break down complex questions into smaller parts. Use the terminology and concepts discussed in this chapter. Structure your answer logically — begin with a definition or key statement, then provide supporting details. Review your answer to ensure it addresses all parts of the question completely.
Key Points to RememberRead the question carefully and identify all parts before answering.
Use the terminology specific to this subject and chapter.
Review the textbook content for this chapter before attempting questions.
Practice writing concise, well-structured answers within time limits.
Related Questions from Solved 2024 Sample Question Paper CBSE Class 10 ScienceQ1: Question 37 The table given below shows the hints given by the quiz master in a quiz. S. No. HINT...
Q11: Question 11 Height of a plant is regulated by: DNA which is directly influenced by growth hormone....
Q12: Question 12 A sportsman, after a long break of his routine exercise, suffered muscular cramps...
Q13: Question 13 An object is placed in front of a convex mirror. Its image is formed : at a distance...
Q14: Question 14 When light enters the atmosphere it strikes on extremely fine particles, which deflect...
Practice more questions from Solved 2024 Sample Question Paper CBSE Class 10 Science &mdash; Science, Class 10 CBSE

Question 10

Question 18Assertion: Probability of survival of an organism produced through sexual reproduction is more than that of organism produced through asexual mode.Reason: Variations provide advantages to individuals for survival.Both A and R are true, and R is the correct explanation of A.Both A and R are true, and R is not the correct explanation of A.A is true but R is false.A is false but R is true.

Accepted Answer

Both A and R are true, and R is the correct explanation of A.Reason — Variations help individual to adapt to the changes in the environment and hence increases the chance of survival.

Question 11

Question 19Assertion : A compass needle is placed near a current carrying wire. The deflection of the compass needle decreases when the magnitude of the current in the wire is increased.Reason : The strength of a magnetic field at a point near the conductor increases on increasing the current.Both A and R are true, and R is the correct explanation of A.Both A and R are true, and R is not the correct explanation of A.A is true but R is false.A is false but R is true.

Accepted Answer

A is false but R is true.Reason — A compass needle is placed near a current carrying wire. The deflection of the compass needle increases when the magnitude of the current in the wire is increased because strength of a magnetic field at a point near the conductor increases on increasing the current.

Question 12

Question 20Assertion: Biodegradable substances result in the formation of compost and natural replenishment.Reason: It is due to breakdown of complex inorganic substances into simple organic substances.Both A and R are true, and R is the correct explanation of A.Both A and R are true, and R is not the correct explanation of A.A is true but R is false.A is false but R is true.

Accepted Answer

A is true but R is false.Reason — Biodegradable substances result in the formation of compost and natural replenishment due to breakdown of complex organic substances into simple organic substances.

Question 13

Question 28(a)An element 'M' with electronic configuration 2 8 3 combines separately with Cl-, SO4-2 anions. Write the chemical formulae of the compounds formed. Predict with the suitable reason the nature of the bond formed by element 'M' in general. How will the electrical conductivity of the compounds formed vary with respect to 'M'?

Accepted Answer

(i) Given, electronic configuration of M is 2, 8, 3. Hence, its valency is +3.When M and Cl- combineChemical formula of iron (III) sulphate:M3+ Cl1−M223 ↙↘ Cl1⇒M21 ↙↘Cl23MCl3\text{M}^{3+} \space \text{Cl}^{1-} \[1em] \overset{\phantom{22}{3}}{\text{M}} \space {\swarrow}\mathllap{\searrow} \space \overset{1}{\text{Cl}} \Rightarrow \underset{\phantom{2}{1}}{\text{M}} \space {\swarrow}\mathllap{\searrow} \underset{\phantom{2}{3}}{\text{Cl}} \[1em] \text{MCl}_3M3+ Cl1−M223 ↙↘ Cl1⇒21M​ ↙↘23Cl​MCl3​∴ Chemical formula will be MCl3(ii) When M and SO4-2 combineM3+ SO42−M223 ↙↘ SO42⇒M22 ↙↘SO423M2(SO4)3\text{M}^{3+} \space \text{SO}_4^{2-} \[1em] \overset{\phantom{22}{3}}{\text{M}} \space {\swarrow}\mathllap{\searrow} \space \overset{2}{\text{SO}_4} \Rightarrow \underset{\phantom{2}{2}}{\text{M}} \space {\swarrow}\mathllap{\searrow} \underset{\phantom{2}{3}}{\text{SO}_4} \[1em] \text{M}_2\text{(SO}_4)_3M3+ SO42−​M223 ↙↘ SO4​2​⇒22M​ ↙↘23SO4​​M2​(SO4​)3​∴ Chemical formula will be M2(SO4)3M in general forms Ionic bond because it acquires a stable electronic configuration of neon (2, 8) by losing its three valence electrons to form M3+ cation.Compounds of M will be ionic compounds so they will conduct electricity in liquid or molten state only but not in solid state. Element 'M' on the other hand can conduct electricity in solid state due to the presence of 3 free electrons in its outermost shell.

Question 14

Question 32(i) State the law that explains the heating effect of current with respect to the measurable properties in an electrical circuit.(ii) List the factors on which the resistance of a conductor depends.

Accepted Answer

(i) Joules law of heating states that the heat dissipated across a resistor is directly proportional tothe square of the current flowing through itresistance of the conductorduration of flow of currenti.e., H = I2Rt(ii) Resistance of conductor depends on —length of the conductor — the resistance of a conductor is directly proportional to the length of the conductor.R ∝ larea of cross section — the resistance of a conductor is inversely proportional to it's area of cross section (a) normal to the direction of flow of current.R ∝ 1a\dfrac{1}{a}a1​temperature of the conductor — the resistance of conductor increases with an increase in it's temperature.nature of material.

Question 15

Question 33Anannya responded to the question: Why do electrical appliances with metallic bodies are connected to the mains through a three pin plug, whereas an electric bulb can be connected with a two pin plug?She wrote: Three pin connections reduce heating of connecting wires.(i) Is her answer correct or incorrect? Justify.(ii) What is the function of a fuse in a domestic circuit?

Accepted Answer

(i) Anannya's answer is wrong. Electrical appliances with metallic bodies need an earth wire which provides a low resistance conducting path to the flow of current in the case when there is an accidental leakage of current through the conducting body of the appliances.(ii) An electric fuse safeguards the circuit and appliances connected in the circuit from being damaged if the current in the circuit exceeds the specified value due to voltage fluctuations or short circuiting. An important component of an electrical fuse is a metal wire or strip that melts when excess current flows through it.

Question 16

Question 35(b)a) A doctor has advised Sameer to reduce sugar intake in his diet and do regular exercise after checking his blood test reports. Which disease do you think Sameer is suffering from? Name the hormone responsible for this disease and the organ producing the hormone.b) Which hormone is present in the areas of rapid cell division in a plant and which hormone inhibits the growth?

Accepted Answer

a) Sameer is suffering from diabetes. In diabetes, there is rise in blood sugar level. The hormone responsible for this disease is insulin which is secreted from β-cells of pancreas.b) Cytokinin is present in the areas of rapid cell division in a plant. Abscisic Acid inhibits the growth in plants.

Question 17

Question 36(a)The below image shows a thin lens of focal length 5 m.(i) What is the kind of lens shown in the above figure?(ii) If a real inverted image is to be formed by this lens at a distance of 7 m from the optical centre, then show with calculation where should the object be placed?(iii) Draw a neatly labelled diagram of the image formation mentioned in (ii).

Accepted Answer

(i) Convex lens(ii) Given,Image distance (v) = 7 mFocal length (f) = 5 mObject distance (u) = ?Using formula,1f\dfrac{1}{	ext{f}}f1​ = 1v\dfrac{1}{	ext{v}}v1​ - 1u\dfrac{1}{	ext{u}}u1​We get,15\dfrac{1}{	ext{5}}51​ = 17\dfrac{1}{	ext{7}}71​ - 1u\dfrac{1}{	ext{u}}u1​1u\dfrac{1}{	ext{u}}u1​ = 17\dfrac{1}{	ext{7}}71​ - 15\dfrac{1}{	ext{5}}51​ = 5−735\dfrac{5-7}{	ext{35}}355−7​ = −235\dfrac{-2}{	ext{35}}35−2​So, u = - 352\dfrac{35}{	ext{2}}235​ = -17.5 mHence, object should be placed at 17.5 m on the left side of the convex lens.(iii) Below ray diagram shows the image formation:

Question 18

Question 36(b)A 10 cm long pencil is placed 5 cm in front of a concave mirror having a radius of curvature of 40 cm.(i) Determine the position of the image formed by this mirror.(ii) What is the size of the image?(iii) Draw a ray diagram to show the formation of the image as mentioned in the part (i).

Accepted Answer

(i) Given,Object distance (u) = -5 cmRadius of curvature (r) = 40 cmImage distance (v) = ?Focal length (f) = r2\dfrac{r}{2}2r​ = 402\dfrac{40}{2}240​ = -20 cm [f in case of a concave mirror is negative.]Using formula,1f\dfrac{1}{	ext{f}}f1​ = 1v\dfrac{1}{	ext{v}}v1​ - 1u\dfrac{1}{	ext{u}}u1​We get,-120\dfrac{1}{	ext{20}}201​ = 1v\dfrac{1}{	ext{v}}v1​ - 15\dfrac{1}{	ext{5}}51​1v\dfrac{1}{	ext{v}}v1​ = -120\dfrac{1}{	ext{20}}201​ + 15\dfrac{1}{	ext{5}}51​1v\dfrac{1}{	ext{v}}v1​ = −1+420\dfrac{-1+4}{	ext{20}}20−1+4​ = 320\dfrac{3}{20}203​So, v = 203\dfrac{20}{3}320​ = 6.67 cmHence, image is obtained at 6.67 cm behind the mirror.(ii) Size of object (ho) = 10 cmSize of the image (hi)= ?From formula,m = hiho\dfrac{h_i}{h_o}ho​hi​​ = - vu\dfrac{	ext{v}}{	ext{u}}uv​Substituting we get,hi10\dfrac{h_i}{10}10hi​​ = −6.67−5-\dfrac{6.67}{-5}−−56.67​hi = 10 x 6.675\dfrac{6.67}{5}56.67​ = 13.34 cmHence, size of image is 13.34 cm(iii) Ray diagram showing the formation of the image is given below:

Question 19

Question 37The table given below shows the hints given by the quiz master in a quiz.S. No.HINT(i)Substance 'C' is used as a preservative.(ii)'C' has two carbon atoms; 'C' is obtained by the reaction of 'A' in presence of alkaline Potassium permanganate followed by acidification.(iii)Misuse of 'A' in industries is prevented by adding Methanol, Benzene, and pyridine to 'A'.(iv)'F' is formed on heating 'A' in presence of conc Sulphuric acid.(v)'F' reacts with Hydrogen gas in presence of Nickel and Palladium catalyst.Based on the above hints answer the following questions(a) Give the IUPAC names of A and F(b) Illustrate with the help of chemical equations the changes taking place. (A ⟶ C and A ⟶ F)OR(b) Name the chemical reactions which occur in steps 2 and 5. Identify the compounds formed in these steps if 'A' is replaced with its next homologue.

Accepted Answer

(a) From step 3 we can conclude that A is EthanolFrom step 5 we can conclude that F is EtheneCH3CH2OH A→ Hot conc.H2SO4CH2=CH2+H2O F\underset{	ext{ A} }{	ext{CH}_3	ext{CH}_2	ext{OH}} \underset{ 	ext{H}_2	ext{SO}_4}{\xrightarrow{	ext{ Hot conc.}}} \underset{	ext{ F}}{	ext{CH}_2=	ext{CH}_2 + {	ext{H}_2	ext{O}}} ACH3​CH2​OH​H2​SO4​ Hot conc.​​ FCH2​=CH2​+H2​O​(b) A ⟶ CCH3CH2OH A→ alkaline KMNO4+Heat+ H+ or acidified K2Cr2O7+HeatCH3COOH C\underset{	ext{ A} }{	ext{CH}_3	ext{CH}_2	ext{OH}} \underset{ 	ext{ or acidified K}_2	ext{Cr}_2	ext{O}_7 + 	ext{{Heat}} }{\xrightarrow{	ext{ alkaline KMNO}_4+ 	ext{Heat} + 	ext{ H}^+}} \underset{	ext{ C} }{ 	ext{CH}_3	ext{COOH} } ACH3​CH2​OH​ or acidified K2​Cr2​O7​+Heat alkaline KMNO4​+Heat+ H+​​ CCH3​COOH​A ⟶ FCH3CH2OH A→ Hot conc.H2SO4CH2=CH2+H2O F\underset{	ext{ A} }{	ext{CH}_3	ext{CH}_2	ext{OH}} \underset{ 	ext{H}_2	ext{SO}_4}{\xrightarrow{	ext{ Hot conc.}}} \underset{	ext{ F}}{	ext{CH}_2=	ext{CH}_2 + {	ext{H}_2	ext{O}}} ACH3​CH2​OH​H2​SO4​ Hot conc.​​ FCH2​=CH2​+H2​O​OR(b) Step 2 is oxidation of ethanol.CH3CH2OH A→ alkaline KMNO4+Heat+ H+ or acidified K2Cr2O7+HeatCH3COOH C\underset{	ext{ A} }{	ext{CH}_3	ext{CH}_2	ext{OH}} \underset{ 	ext{ or acidified K}_2	ext{Cr}_2	ext{O}_7 + 	ext{{Heat}} }{\xrightarrow{	ext{ alkaline KMNO}_4+ 	ext{Heat} + 	ext{ H}^+}} \underset{	ext{ C} }{ 	ext{CH}_3	ext{COOH} } ACH3​CH2​OH​ or acidified K2​Cr2​O7​+Heat alkaline KMNO4​+Heat+ H+​​ CCH3​COOH​Step 5 is hydrogenation as ethene reacts with hydrogen gas. It is also called an addition reaction.CH2 = CH2 + H2 ⟶ CH3 - CH3 [ethane]When ethanol is replaced by propanol then propene is formed instead of ethene.C3H7OH Propanol→ Hot conc.H2SO4C3H6+H2O Propene\underset{	ext{ Propanol} }{	ext{C}_3	ext{H}_7	ext{OH}} \underset{ 	ext{H}_2	ext{SO}_4}{\xrightarrow{	ext{ Hot conc.}}} \underset{	ext{ Propene}}{	ext{C}_3	ext{H}_6 + {	ext{H}_2	ext{O}}} PropanolC3​H7​OH​H2​SO4​ Hot conc.​​ PropeneC3​H6​+H2​O​

Question 20

Question 39Vinita and Ahmed demonstrated a circuit that operates the two headlights and the two sidelights of a car, in their school exhibition. Based on their demonstrated circuit, answer the following questions.(i) State what happens when switch A is connected to(a) Position 2(b) Position 3(ii) Find the potential difference across each lamp when lit.(iii) Calculate the current(a) in each 12 Ω lamp when lit.(b) In each 4 Ω lamp when lit.OR(iv) Show, with calculations, which type of lamp, 4.0 Ω or 12 Ω, has the higher power.

Accepted Answer

(i) (a) When switch A is connected to position 2, circuit A-2 is complete and only 12 Ω lamps are on.(b) When switch A is connected to position 3, circuit A-3 is complete and only 4 Ω lamps are on.(ii) We know that when the resistances are connected in parallel, they have the same potential difference across their ends, hence, potential difference across each lamp when lit will be 12 V.(iii) When the wire is connected to position 2, 12 Ω lamps are on.Resistance of each lamp = 12 ΩVoltage across each lamp = 12 V.Using Ohm's Law: V = IRSubstituting we get,12 = I x 12I = 1212\dfrac{12}{12}1212​ = 1 AHence, current across each 12 Ω lamp is 1 A.When the wire is connected to position 3, 4 Ω lamps are on.Resistance of each lamp = 4 ΩVoltage across each lamp = 12 V.Using Ohm's Law: V = IRSubstituting we get,12 = I x 4I = 124\dfrac{12}{4}412​ = 3 AHence, current across each 4 Ω lamp is 3 A.OR(iv) Given,All lamps are in parallel so V across each lamp = 12 VWe know, P = V2R\dfrac{V^2}{R}RV2​Substituting we get,For 12 Ω lamps:P = 12×1212\dfrac{12 	imes 12}{12}1212×12​ = 12 WFor 4 Ω lamps:P = 12×124\dfrac{12 	imes 12}{4}412×12​ = 36 WHence, power across 4 Ω lamps will be higher.

Solved 2024 Sample Question Paper CBSE Class 10 Science

Section A (Objective Type Questions 1 Mark Each)

Section C (Short Answer Questions 3 Marks Each)

Section D (Long Answer Questions 5 Marks Each)

Section E (Source/Case Based Questions 4 Marks Each)