Question 21Write following expressions in Python:(a) 13b2h\dfrac{1}{3} b^2 h31b2hAnswer1 / 3 * b * b * h(b) πr2h\pi r^2 hπr2hAnswermath.pi * r * r * h(c) 13πr2h\dfrac{1}{3} \pi r^2 h31πr2hAnswer1 / 3 * math.pi * r * r * h(d) (x2−x1)2+(y2−y1)2\sqrt{(x2 - x1)^2 + (y2 - y1)^2}(x2−x1)2+(y2−y1)2Answermath.sqrt((x2 - x1) ** 2 + (y2 - y1) ** 2)(e) (x−h)2+(y−k)2=r2(x - h)^2 + (y - k)^2 = r^2(x−h)2+(y−k)2=r2Answer(x - h) ** 2 + (y - k) ** 2 == r ** 2(f) x=−b+b2−4ac2ax = \dfrac{-b + \sqrt{b^2 - 4ac}}{2a}x=2a−b+b2−4acAnswerx = (-b + math.sqrt(b * b - 4 * a * c)) / (2 * a)(g) an×am=an+ma^n imes a^m = a^{n+m}an×am=an+mAnswera ** n * a ** m == a ** (n + m)(h) (an)m=anm(a^n)^m = a^{nm}(an)m=anmAnswer(a ** n) ** m == a ** (n * m)(i) anam=an−m\dfrac{a^n}{a^m} = a^{n - m}aman=an−mAnswera ** n / a ** m == a ** (n - m)(j) a−n=1ana^{-n} = \dfrac{1}{a^n}a−n=an1Answera ** -n == 1 / a ** n

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Question 21Write following expressions in Python:(a) 13b2h\dfrac{1}{3} b^2 h31​b2hAnswer1 / 3 * b * b * h(b) πr2h\pi r^2 hπr2hAnswermath.pi * r * r * h(c) 13πr2h\dfrac{1}{3} \pi r^2 h31​πr2hAnswer1 / 3 * math.pi * r * r * h(d) (x2−x1)2+(y2−y1)2\sqrt{(x2 - x1)^2 + (y2 - y1)^2}(x2−x1)2+(y2−y1)2​Answermath.sqrt((x2 - x1) ** 2 + (y2 - y1) ** 2)(e) (x−h)2+(y−k)2=r2(x - h)^2 + (y - k)^2 = r^2(x−h)2+(y−k)2=r2Answer(x - h) ** 2 + (y - k) ** 2 == r ** 2(f) x=−b+b2−4ac2ax = \dfrac{-b + \sqrt{b^2 - 4ac}}{2a}x=2a−b+b2−4ac​​Answerx = (-b + math.sqrt(b * b - 4 * a * c)) / (2 * a)(g) an×am=an+ma^n 	imes a^m = a^{n+m}an×am=an+mAnswera ** n * a ** m == a ** (n + m)(h) (an)m=anm(a^n)^m = a^{nm}(an)m=anmAnswer(a ** n) ** m == a ** (n * m)(i) anam=an−m\dfrac{a^n}{a^m} = a^{n - m}aman​=an−mAnswera ** n / a ** m == a ** (n - m)(j) a−n=1ana^{-n} = \dfrac{1}{a^n}a−n=an1​Answera ** -n == 1 / a ** n

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Data Handling — Question 21

Question 21