Data Representation — Question 15

(38AC)₁₆ = (11100010101100)₂

Grouping in bits of 3:

$\underlinesegment{011}\medspace\underlinesegment{100}\medspace\underlinesegment{010}\medspace\underlinesegment{101}\medspace\underlinesegment{100}$

(38AC)₁₆ = (34254)₈

(b) 7FD6

(7FD6)₁₆ = (111111111010110)₂

Grouping in bits of 3:

$\underlinesegment{111}\medspace\underlinesegment{111}\medspace\underlinesegment{111}\medspace\underlinesegment{010}\medspace\underlinesegment{110}$

(7FD6)₁₆ = (77726)₈

(c) ABCD

(ABCD)₁₆ = (1010101111001101)₂

Grouping in bits of 3:

$\underlinesegment{001}\medspace\underlinesegment{010}\medspace\underlinesegment{101}\medspace\underlinesegment{111}\medspace\underlinesegment{001}\medspace\underlinesegment{101}$

(ABCD)₁₆ = (125715)₈