Question 4Convert the following decimal numbers to binary:(a) 19

Question

Accepted Answer

2QuotientRemainder2191 (LSB)291240220211 (MSB) 0 Therefore, (19)10 = (10011)2(b) 1222QuotientRemainder21220 (LSB)261123002151271231211 (MSB) 0 Therefore, (122)10 = (1111010)2(c) 1612QuotientRemainder21611 (LSB)2800240022002100251220211 (MSB) 0 Therefore, (161)10 = (10100001)2(d) 0.675Multiply=ResultantCarry0.675 x 2=0.3510.35 x 2=0.700.7 x 2=0.410.4 x 2=0.800.8 x 2=0.61(We stop after 5 iterations if fractional part doesn't become 0)Therefore, (0.675)10 = (0.10101)2

Multiply	=	Resultant	Carry
0.675 x 2	=	0.35	1
0.35 x 2	=	0.7	0
0.7 x 2	=	0.4	1
0.4 x 2	=	0.8	0
0.8 x 2	=	0.6	1

2	Quotient	Remainder
2	19	1 (LSB)
2	9	1
2	4	0
2	2	0
2	1	1 (MSB)
	0

2	Quotient	Remainder
2	122	0 (LSB)
2	61	1
2	30	0
2	15	1
2	7	1
2	3	1
2	1	1 (MSB)
	0

2	Quotient	Remainder
2	161	1 (LSB)
2	80	0
2	40	0
2	20	0
2	10	0
2	5	1
2	2	0
2	1	1 (MSB)
	0

Data Representation — Question 4

Question 4