Data Representation — Question 8

Grouping in bits of 4:

$\underlinesegment{0100} \quad \underlinesegment{1101} \quad \underlinesegment{1101}$

Therefore, (10011011101)₂ = (4DD)₁₆

(b) 1111011101011011

Grouping in bits of 4:

$\underlinesegment{1111} \quad \underlinesegment{0111} \quad \underlinesegment{0101} \quad \underlinesegment{1011}$

Therefore, (1111011101011011)₂ = (F75B)₁₆

(c) 11010111010111

Grouping in bits of 4:

$\underlinesegment{0011} \quad \underlinesegment{0101} \quad \underlinesegment{1101} \quad \underlinesegment{0111}$

Therefore, (11010111010111)₂ = (35D7)₁₆