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CBSE Class 11 Computer Science Question 89 of 112

Dictionaries — Question 11

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11
Question

Question 9(c)

Predict the output:

text = "abracadabraaabbccrr" 
counts = {}
ct = 0
lst = []
for word in text:
  if word not in lst:
    lst.append(word)
    counts[word] = 0
  ct = ct + 1
  counts[word] = counts[word] + 1 
print(counts)
print(lst)
Answer
Output
{'a': 7, 'b': 4, 'r': 4, 'c': 3, 'd': 1} 
['a', 'b', 'r', 'c', 'd']
Explanation

This python program counts the frequency of each character in a string. Here is a step-by-step explanation of the program:

  1. Initialize the variables
    1. The text variable stores the input string "abracadabraaabbccrr".
    2. The counts variable is a dictionary that stores the frequency of each character in the string.
    3. The ct variable is a counter that keeps track of the total number of characters in the string.
    4. The lst variable is a list that stores the unique characters in the string.
  2. Loop through each character word in the text string
    1. If the character has not been seen before, it is added to the lst list and a new key is added to the counts dictionary with a value of 0.
    2. The ct variable is incremented by 1.
    3. The value of the character's key in the counts dictionary is incremented by 1. This value keeps a count of the number of times this character has appeared in the string so far.
  3. Finally, the counts dictionary and the lst list are printed to the console. The counts dictionary displays the frequency of each character in the string, and the lst list displays the unique characters in the string.