String Manipulation — Question 9

Question 3

Carefully go through the code given below and answer the questions based on it :

theStr = " This is a test "         
inputStr = input(" Enter integer: ")
inputlnt = int(inputStr)            
testStr = theStr
while inputlnt >= 0 :               
    testStr = testStr[1:-1]        
    inputlnt = inputlnt - 1
testBool = 't' in testStr
print (theStr)             # Line 1 
print (testStr)            # Line 2 
print (inputlnt)           # Line 3 
print (testBool)           # Line 4 

(i) Given the input integer 3, what output is produced by Line 1?

1. This is a test
2. This is a
3. is a test
4. is a
5. None of these

Answer

Option 1 — This is a test

(ii) Given the input integer 3, what output is produced by Line 2?

1. This is a test
2. s is a t
3. is a test
4. is a
5. None of these

Answer

Option 2 — s is a t

Explanation

As input is 3 and inside the while loop, inputlnt decreases by 1 in each iteration so the while loop executes 4 times for inputlnt values 3, 2, 1, 0.

1st Iteration
testStr = "This is a test"

2nd Iteration
testStr = "his is a tes"

3rd Iteration
testStr = "is is a te"

4th Iteration
testStr = "s is a t"

(iii) Given the input integer 2, what output is produced by Line 3?

1. 0
2. 1
3. 2
4. 3
5. None of these

Answer

Option 5 — None of these

Explanation

Value of inputlnt will be -1 as till inputlnt >= 0 the while loop will continue executing.

(iv) Given the input integer 2, what output is produced by Line 4?

1. False
2. True
3. 0
4. 1
5. None of these

Answer

Option 2 — True

Explanation

As input is 2 and inside the while loop, inputlnt decreases by 1 in each iteration so the while loop executes 3 times for inputlnt values 2, 1, 0.

1st Iteration
testStr = "This is a test"

2nd Iteration
testStr = "his is a tes"

3rd Iteration
testStr = "is is a te"

After the while loop finishes executing, value of testStr is "is is a te". 't' in testStr returns True as letter t is present in testStr.