CBSE Class 11 Computer Science
Question 40 of 80
Conditional and Looping Constructs — Question 10
Back to all questions1 1
2 1
2 2
3 1
3 2
3 3
4 1
4 2
4 3
4 4
5 1
5 2
5 3
5 4
5 5
Below is the detailed explanation of this code:
1. Outer Loop: for x in range(1, 6):
- This loop iterates over the range of numbers starting from 1 up to but not including 6. So,
xwill take on the values: 1, 2, 3, 4, 5.
2. Inner Loop: for y in range(1, x + 1):
- For each value of
xin the outer loop,ywill iterate over the range of numbers starting from 1 up to and includingx(sincex + 1is exclusive).
3. print(x, ' ', y)
- This prints the current values of
xandyseparated by a space.
Let’s analyze the loops iteration by iteration.
Outer loop (x values ranging from 1 to 5):
When x = 1:
- The inner loop
range(1, 2)results inytaking values: 1. - Output:
1 1
When x = 2:
- The inner loop
range(1, 3)results inytaking values: 1, 2. - Output:
2 1 2 2
When x = 3:
- The inner loop
range(1, 4)results inytaking values: 1, 2, 3. - Output:
3 1 3 2 3 3
When x = 4:
- The inner loop
range(1, 5)results inytaking values: 1, 2, 3, 4. - Output:
4 1 4 2 4 3 4 4
When x = 5:
- The inner loop
range(1, 6)results inytaking values: 1, 2, 3, 4, 5. - Output:
5 1 5 2 5 3 5 4 5 5
Putting all these outputs together, we get:
1 1
2 1
2 2
3 1
3 2
3 3
4 1
4 2
4 3
4 4
5 1
5 2
5 3
5 4
5 5