Conditional and Looping Constructs — Question 14

o o

Let’s break down the code step-by-step:

1. Outer Loop: for i in range(2): → This loop iterates over the range of numbers starting from 0 up to but not including 2. So, i will take on the values: 0, 1.

2. Inner Loop: for j in range(1): → For each value of i in the outer loop, j will iterate over the range of numbers starting from 0 up to but not including 1. So, j will take on the only value: 0.

3. if i + 2 == j: → This condition checks if i + 2 is equal to j.

4. print("+", end=" ") → If the condition i + 2 == j is true, this statement prints a "+", followed by a space, without moving to a new line.

5. print("o", end=" ") → If the condition i + 2 == j is false, this statement prints an "o", followed by a space, without moving to a new line.

Let’s analyze the loops iteration by iteration:

• First iteration of the outer loop (i = 0):
  • Inner loop (j = 0):
    • i + 2 == j becomes 0 + 2 == 0, which is 2 == 0, is false.
    • Therefore, the else block is executed, and the output is o
• Second iteration of the outer loop (i = 1):
  • Inner loop (j = 0):
    • i + 2 == j becomes 1 + 2 == 0, which is 3 == 0, is false.
    • Therefore, the else block is executed, and the output is o

So, combining the outputs of all iterations, the full output will be:

o o 

Each "o" is followed by a space, and there is no new line between them due to the end=" " parameter in the print function.