CBSE Class 11 Computer Science
Question 31 of 68
Data Representation and Boolean Logic — Question 2
Back to all questions(a) 911
| 8 | 911 | Remainder |
|---|---|---|
| 8 | 113 | 7 (LSB) |
| 8 | 14 | 1 |
| 8 | 1 | 6 |
| 0 | 1 (MSB) |
Therefore, (911)10 = (1617)8.
(b) 540
| 8 | 540 | Remainder |
|---|---|---|
| 8 | 67 | 4 (LSB) |
| 8 | 8 | 3 |
| 8 | 1 | 0 |
| 0 | 1 (MSB) |
Therefore, (540)10 = (1034)8.
(c) 61
| 8 | 61 | Remainder |
|---|---|---|
| 8 | 7 | 5 (LSB) |
| 0 | 7 (MSB) |
Therefore, (61)10 = (75)8.
(d) 132
| 8 | 132 | Remainder |
|---|---|---|
| 8 | 16 | 4 (LSB) |
| 8 | 2 | 0 |
| 0 | 2 (MSB) |
Therefore, (132)10 = (204)8.