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CBSE Class 11 Computer Science Question 47 of 98

Python Programming Fundamentals — Question 9

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9
Question

Question 6(d)

Find the output of the following code:

p=10
q=20
p*=q/3
q+=p+q*2
print (p,q)
Answer
Output
66.66666666666667 126.66666666666667
Explanation
p *= q / 3

The *= operator multiplies p by the value on the right and assigns it to p again.

  • First, compute the division: q / 3 = 20 / 3 ≈ 6.6667
  • p *= 6.6667 means p = p * 6.6667
  • So, p = 10 * 6.6667 = 66.6667
q += p + q * 2

The += operator adds the value on the right to q and assigns it to q again.

  • First, compute q * 2 = 20 * 2 = 40
  • Then add values: p + q * 2 = 66.6667 + 40
  • Finally, add it to q: q += 106.6667 means q = q + 106.6667
  • So, q = 20 + 106.6667 = 126.6667
print(p, q)

The variables now have these final values:

  • p = 66.6667
  • q = 126.6667

The precision difference is due to floating-point arithmetic. For simplicity of explanation we have taken lesser precision values.