Question 1

Question 1Assertion (A): Dictionary is a collection of key-value pairs.Reasoning (R): Each key in a dictionary maps to a corresponding value. Keys are unique and act as the index.Both A and R are true and R is the correct explanation of A.Both A and R are true but R is not the correct explanation of A.A is true but R is false.A is false but R is true.

Accepted Answer

Both A and R are true and R is the correct explanation of A.ExplanationA dictionary is a collection of key-value pairs, where each key is unique and maps to a corresponding value. The keys act as the index, allowing to access and manipulate the values associated with them.

Question 2

Question 3Assertion (A): The popitem() method can be used to delete elements from a dictionary.Reasoning (R): The popitem() method deletes the last inserted key-value pair and returns the value of deleted element.Both A and R are true and R is the correct explanation of A.Both A and R are true but R is not the correct explanation of A.A is true but R is false.A is false but R is true.

Accepted Answer

Both A and R are true and R is the correct explanation of A.ExplanationThe popitem() method in Python is used to delete elements from a dictionary. It returns and removes the last inserted key-value pair from the dictionary.

Question 3

Question 6Assertion (A): Items in dictionaries are unordered.Reasoning (R): You may not get back the data in the same order in which you had entered the data initially in the dictionary.Both A and R are true and R is the correct explanation of A.Both A and R are true but R is not the correct explanation of A.A is true but R is false.A is false but R is true.

Accepted Answer

Both A and R are true and R is the correct explanation of A.ExplanationIn Python, items in dictionaries are unordered. Dictionaries do not maintain the order of elements as they are inserted. When retrieving data from a dictionary, the order of elements returned may not match the order in which they were inserted.

Question 4

Question 7Assertion (A): Consider the code given below:d={1: 'Amit', 2: 'Sumit', 5:'Kavita'}
d.pop(1) 
print(d) The output will be:Amit #item is returned after deletion
{2: 'Sumit', 5: 'Kavita'}
Reasoning (R): pop() method not only deletes the item from the dictionary but also returns the deleted value.Both A and R are true and R is the correct explanation of A.Both A and R are true but R is not the correct explanation of A.A is true but R is false.A is false but R is true.

Accepted Answer

Both A and R are true and R is the correct explanation of A.ExplanationIn the given code, when d.pop(1) is called, it removes the key 1 and returns the corresponding value 'Amit'. The subsequent print(d) statement displays the updated dictionary without the key-value pair (1, 'Amit'). The pop() method in Python dictionaries not only deletes the specified key-value pair from the dictionary but also returns the value associated with the deleted key.

Question 5

Question 10Select the correct option to get the values of marks key:Student={ "name" : "Emma", "class" :11, "sec": "a", "marks" :76}Student.get(3)Student.get("marks")Student["marks"]Both 2 and 3

Accepted Answer

Both 2 and 3Reason — Student.get("marks") and Student["marks"] both access the value associated with the key "marks" in the Student dictionary. While Student.get(3) would return "None" because there is no key 3 in the dictionary.

Question 6

Question 11Consider the given code:D1={1: 'India', 2: 'Russia', 3: 'World'}
D2={'School' : 'EOIS' , 'Place ' : 'Moscow'}
print(D1.update (D2) )What will be the output of the above code:None{1: 'India' , 2: 'Russia' , 3: 'World' , 'School' : 'EOIS' , 'Place' : 'Moscow'}ErrorNone of these

Accepted Answer

NoneReason — The output is "None" when using print(D1.update(D2)) because the update() method for dictionaries modifies the dictionary in place. It does not return the updated dictionary itself; instead, it returns "None".

Question 7

Question 2What are the differences between strings and dictionary?

Accepted Answer

StringDictionaryA string is a sequence of characters enclosed in quotes.A dictionary is a collection of key-value pairs enclosed in curly braces {}.It is immutable.It is mutable.Strings are ordered collection of objects.Dictionaries are unordered collections of objects.For example, "hello", '123' etc.For example, {1: 'a', 2 : 'b'} etc

Question 8

Question 3(b)Find errors and rewrite the same after correcting the following code:d1(9) = 90

Accepted Answer

In Python, we assign the key-value pair using square brackets [], not parentheses ().The corrected code is:d1[9] = 90

Question 9

Question 3(c)Find errors and rewrite the same after correcting the following code:del d1(2)

Accepted Answer

In Python, to delete an element from a dictionary, we should use square brackets [], not parentheses ().The corrected code is:del d1[2]

Question 10

Question 3(f)Find errors and rewrite the same after correcting the following code:d1.key()

Accepted Answer

The correct method to retrieve all keys from a dictionary is keys(), not key().The corrected code is:d1.keys()

Question 11

Question 3(g)Find errors and rewrite the same after correcting the following code:d1.value()

Accepted Answer

The correct method to retrieve all values from a dictionary is values(), not value().The corrected code is:d1.values()

Question 12

Question 3(j)Find errors and rewrite the same after correcting the following code:d1.clears()

Accepted Answer

The correct method to clear all elements from a dictionary is clear(), not clears().The corrected code is:d1.clear()

Question 13

Question 4(a)Suppose>>> d1 = { 1 : 'one' , 2: 'two' , 3: 'three' , 4: 'four'}
>>> d2 = { 5 :'five', 6:'six' }Write the output of the following code:>>> d1.items() 
>>> d1.keys() 
>>> d1.values() 
>>> d1.update(d2)
>>> len(d1)

Accepted Answer

Outputdict_items([(1, 'one'), (2, 'two'), (3, 'three'), (4, 'four')])
dict_keys([1, 2, 3, 4])
dict_values(['one', 'two', 'three', 'four'])
6
Explanationd1.items() — Returns a list of tuples containing the key-value pairs in d1.d1.keys() — Returns a list of all the keys in d1.d1.values() — Returns a list of all the values in d1.d1.update(d2) — Updates d1 with key-value pairs from d2. After this operation, d1 contains {1: 'one', 2: 'two', 3: 'three', 4: 'four', 5: 'five', 6: 'six'}.len(d1) — Returns the number of key-value pairs in d1, which is 6 after updating.

Question 14

Question 4(b)Suppose>>> d1 = { 1 : 'one' , 2: 'two' , 3: 'three' , 4: 'four'}
>>> d2 = { 5 :'five', 6:'six' }Write the output of the following code:>>> del d1[3] 
>>> print(d1) 
>>> d1.pop(4) 
>>> print(d1) 
>>> d1 [8] =' eight'
>>> print(d1) 
>>> d1.clear() 
>>> print(d1)

Accepted Answer

Output{1: 'one', 2: 'two', 4: 'four'}
'four'
{1: 'one', 2: 'two'}
{1: 'one', 2: 'two', 8: ' eight'}
{}
Explanationdel d1[3]: Removes the key 3 and its corresponding value 'three' from d1. After deletion, d1 contains {1: 'one', 2: 'two', 4: 'four'}.d1.pop(4): Removes the key 4 and its corresponding value 'four' from d1. After popping, d1 is {1: 'one', 2: 'two'}.d1[8] = 'eight': Adds a new key-value pair 8: 'eight' to d1. Now d1 becomes {1: 'one', 2: 'two', 8: 'eight'}.d1.clear(): Clears all key-value pairs from d1, resulting in an empty dictionary {}.

Question 15

Question 5Write a Python program to find the highest 2 values in a dictionary.Solutiond = {'a': 10, 'b': 30, 'c': 20, 'd': 50, 'e': 40}
s = sorted(d.values())
print("Dictionary:", d)
print("Highest 2 values are:", s[-1], s[-2])OutputDictionary: {'a': 10, 'b': 30, 'c': 20, 'd': 50, 'e': 40}
Highest 2 values are: 50 40

Accepted Answer

d={'a':10,'b':30,'c':20,'d':50,'e':40}s=sorted(d.values())print("Dictionary:",d)print("Highest 2 values are:",s[-1],s[-2])OutputDictionary: {'a': 10, 'b': 30, 'c': 20, 'd': 50, 'e': 40}Highest 2 values are: 50 40

Question 16

Question 6Write a Python program to input 'n' classes and names of their class teachers to store it in a dictionary and display the same. Also, accept a particular class from the user and display the name of the class teacher of that class.Solutionn = int(input("Enter number of classes: "))
data = {}
for i in range(n):
    class_name = input("Enter class name: ")
    teacher_name = input("Enter teacher name: ")
    data[class_name] = teacher_name
print("Class data:", data)
find = input("Enter a class name to find its teacher: ")
if find in data:
    print("Teacher for class", find, "is", data[find])
else:
    print("Class not found in the data.")OutputEnter number of classes: 4
Enter class name: green
Enter teacher name: Aniket
Enter class name: yellow
Enter teacher name: Pratibha
Enter class name: red
Enter teacher name: Mayuri
Enter class name: blue
Enter teacher name: Prithvi
Class data: {'green': 'Aniket', 'yellow': 'Pratibha', 'red': 'Mayuri', 'blue': 'Prithvi'}
Enter a class name to find its teacher: red
Teacher for class red is Mayuri

Accepted Answer

n=int(input("Enter number of classes: "))data={}foriinrange(n):class_name=input("Enter class name: ")teacher_name=input("Enter teacher name: ")data[class_name]=teacher_nameprint("Class data:",data)find=input("Enter a class name to find its teacher: ")iffindindata:print("Teacher for class",find,"is",data[find])else:print("Class not found in the data.")OutputEnter number of classes: 4Enter class name: greenEnter teacher name: AniketEnter class name: yellowEnter teacher name: PratibhaEnter class name: redEnter teacher name: MayuriEnter class name: blueEnter teacher name: PrithviClass data: {'green': 'Aniket', 'yellow': 'Pratibha', 'red': 'Mayuri', 'blue': 'Prithvi'}Enter a class name to find its teacher: redTeacher for class red is Mayuri

Question 17

Question 7Write a program to store students' names and their percentage in a dictionary, and delete a particular student name from the dictionary. Also display dictionary after deletion.Solutionn = int(input("Enter number of students: "))
data = {}
for i in range(n):
    stu_name = input("Enter student name: ")
    percentage = input("Enter percentage: ")
    data[stu_name] = percentage
print("Student data:", data)
find = input("Enter a student name to delete: ")
if find in data:
    del data[find]
    print("Updated student data:", data)
else:
    print("Student not found in the data.")OutputEnter number of students: 4
Enter student name: Megha
Enter percentage: 98
Enter student name: Amit
Enter percentage: 88
Enter student name: Nitin
Enter percentage: 92
Enter student name: Amulya
Enter percentage: 79
Student data: {'Megha': '98', 'Amit': '88', 'Nitin': '92', 'Amulya': '79'}
Enter a student name to delete: Nitin
Updated student data: {'Megha': '98', 'Amit': '88', 'Amulya': '79'}

Accepted Answer

n=int(input("Enter number of students: "))data={}foriinrange(n):stu_name=input("Enter student name: ")percentage=input("Enter percentage: ")data[stu_name]=percentageprint("Student data:",data)find=input("Enter a student name to delete: ")iffindindata:deldata[find]print("Updated student data:",data)else:print("Student not found in the data.")OutputEnter number of students: 4Enter student name: MeghaEnter percentage: 98Enter student name: AmitEnter percentage: 88Enter student name: NitinEnter percentage: 92Enter student name: AmulyaEnter percentage: 79Student data: {'Megha': '98', 'Amit': '88', 'Nitin': '92', 'Amulya': '79'}Enter a student name to delete: NitinUpdated student data: {'Megha': '98', 'Amit': '88', 'Amulya': '79'}

Question 18

Question 8Write a Python program to input names of 'n' customers and their details like items bought, cost and phone number, store it in a dictionary and display all the details in a tabular form.Solutionn = int(input("Enter the number of customers: "))
customer_data = {}

for i in range(n):
    name = input("Enter customer name: ")
    items_bought = input("Enter items bought: ")
    cost = float(input("Enter cost: "))
    phone_number = int(input("Enter phone number: "))

customer_data[name] = {
        'Items Bought': items_bought,
        'Cost': cost,
        'Phone Number': phone_number
    }

print("Customer Details:")
print("Name		Items Bought		Cost		Phone Number")
for name, details in customer_data.items():
    print(name, "		", details['Items Bought'], "		", details['Cost'], "		", details['Phone Number'])OutputEnter the number of customers: 4
Enter customer name: Sakshi
Enter items bought: Chocolate, Icecream
Enter cost: 200
Enter phone number: 9876354678
Enter customer name: Shashank
Enter items bought: Biscuits, Maggie, Soup
Enter cost: 450
Enter phone number: 8976346378
Enter customer name: Saanvi
Enter items bought: Veggies, Coffee
Enter cost: 300
Enter phone number: 8794653923
Enter customer name: Shivank
Enter items bought: Door mat, Bottles, Boxes
Enter cost: 600
Enter phone number: 6737486827
Customer Details:
Name            Items Bought            Cost            Phone Number
Sakshi           Chocolate, Icecream             200.0           9876354678
Shashank                 Biscuits, Maggie, Soup                  450.0           8976346378
Saanvi           Veggies, Coffee                 300.0           8794653923
Shivank                  Door mat, Bottles, Boxes                600.0           6737486827

Accepted Answer

n=int(input("Enter the number of customers: "))customer_data={}foriinrange(n):name=input("Enter customer name: ")items_bought=input("Enter items bought: ")cost=float(input("Enter cost: "))phone_number=int(input("Enter phone number: "))customer_data[name]={'Items Bought':items_bought,'Cost':cost,'Phone Number':phone_number}print("Customer Details:")print("Name		Items Bought		Cost		Phone Number")forname,detailsincustomer_data.items():print(name,"		",details['Items Bought'],"		",details['Cost'],"		",details['Phone Number'])OutputEnter the number of customers: 4Enter customer name: SakshiEnter items bought: Chocolate, IcecreamEnter cost: 200Enter phone number: 9876354678Enter customer name: ShashankEnter items bought: Biscuits, Maggie, SoupEnter cost: 450Enter phone number: 8976346378Enter customer name: SaanviEnter items bought: Veggies, CoffeeEnter cost: 300Enter phone number: 8794653923Enter customer name: ShivankEnter items bought: Door mat, Bottles, BoxesEnter cost: 600Enter phone number: 6737486827Customer Details:Name            Items Bought            Cost            Phone NumberSakshi           Chocolate, Icecream             200.0           9876354678Shashank                 Biscuits, Maggie, Soup                  450.0           8976346378Saanvi           Veggies, Coffee                 300.0           8794653923Shivank                  Door mat, Bottles, Boxes                600.0           6737486827

Question 19

Question 9What type of objects can be used as keys in dictionaries?

Accepted Answer

Keys of a dictionary must be of immutable types such asa Python stringa numbera tuple (containing only immutable entries)

Source: This question is from Dictionary, Informatics Practices &mdash; Class 11, CBSE Board.
Key Concepts CoveredThis question tests your understanding of the following concepts from the chapter Dictionary: Question, Objects, Keys, Dictionaries, Dictionary, Informatics Practices. These are fundamental topics in Informatics Practices that students are expected to master as part of the CBSE Class 11 curriculum.A thorough understanding of these concepts will help you answer similar questions confidently in your CBSE examinations. These topics are frequently tested in both objective and subjective sections of Informatics Practices papers. We recommend revising the relevant section of your textbook alongside practising these solved examples to build a strong foundation.
How to Approach This QuestionRead the question carefully and identify what is being asked. Break down complex questions into smaller parts. Use the terminology and concepts discussed in this chapter. Structure your answer logically — begin with a definition or key statement, then provide supporting details. Review your answer to ensure it addresses all parts of the question completely.
Key Points to RememberRead the question carefully and identify all parts before answering.
Use the terminology specific to this subject and chapter.
Review the textbook content for this chapter before attempting questions.
Practice writing concise, well-structured answers within time limits.
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Question 20

Question 10How will you check for a value inside a dictionary using in operator?

Accepted Answer

We cannot directly check for a value inside a dictionary using in operator since in operator searches for a key in a dictionary. We can use values() function along with in operator to check for a value in dictionary as shown below:>>> d = {1: 'a' , 2:'b'}
>>> 'b' in d.values()
OutputTrue

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