Exception Handling — Question 1

The incorrect indentation of the print statement will cause an indentation error when the code is executed.

The corrected code is as follows:

def myfunc(x = None) :
    result = "" 
    if x is None:
       result = "No argument given"
    elif x == 0: 
       result = "Zero"
    elif 0 < x <= 3:
       result = "x is between 0 and 3"
    else:
       result = "x is more than 3"
    return result 
c = myfunc(3.5) 
print(c)

x is more than 3

Working of the code:

The code defines a function myfunc that takes an argument x, which defaults to None. Inside the function, it checks the value of x using a series of if-elif-else conditions. If x is None, it sets the result to "No argument given." If x is 0, it sets the result to "Zero." If x is greater than 0 but less than or equal to 3, it sets the result to "x is between 0 and 3." Otherwise, if x is greater than 3, it sets the result to "x is more than 3." The function then returns the result. In the provided code, the function is called with the argument 3.5, which falls into the last else condition, resulting in the output "x is more than 3" being stored in variable c and printed.