True is returned by check(8).
The provided code defines a recursive function check(n) that takes single argument. Inside the function, it checks if a given number n is less than or equal to 1, in which case it returns True. If n is even (i.e., divisible by 2 without a remainder), the function recursively calls itself with n/2. If n is odd, it recursively calls itself with n/1 (which effectively does not change n). However, the condition n/1 doesn't modify n and leads to an infinite recursion for odd numbers greater than 1, causing the function to keep calling itself indefinitely without reaching a base case.