Since, \(\frac{8}{7}\) is more than 1 and \(\frac{9}{15}\) is less than 1.
So, \(\frac{8}{7}>\frac{9}{15}\)
(b) \(\frac{13}{20}\) ____ \(\frac{17}{15}\)
Solution:
Since, \(\frac{13}{20}\) is less than 1 and \(\frac{17}{15}\) is more than 1.
So, \(\frac{13}{20}<\frac{17}{15}\) .
(c) \(\frac{7}{6}\) ____ \(\frac{8}{8}\)
Solution:
Since, \(\frac{7}{2}\) is more than 1 and \(\frac{8}{8}\) is equal to 1.
So, \(\frac{7}{6}>\frac{8}{8}\).
(d) \(\frac{6}{6}\) ____ \(\frac{19}{12}\)
Solution:
Since, \(\frac{6}{6}\) is equal to 1 and \(\frac{19}{12}\) is more than 1.
So, \(\frac{6}{6}<\frac{19}{12}\).
(e) \(\frac{12}{9}\) ____ \(\frac{4}{5}\)
Solution:
Since, \(\frac{12}{9}\) is more than 1 and \(\frac{4}{5}\) is less than 1.
So \(\frac{12}{9}>\frac{4}{5}\)
(f) \(\frac{15}{5}\) ____ \(\frac{16}{4}\)
Solution:
Since, \(\frac{15}{5}\) = 3, and \(\frac{16}{4}\) = 4
So, \(\frac{15}{5}<\frac{16}{4}\) as 3 < 4.
NCERT Textbook Page 30
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