Here, \(\frac{2}{9}\) ia less than \(\frac{1}{2}\) and \(\frac{4}{7}\) is more than \(\frac{1}{2}\). So, \(\frac{2}{9}<\frac{4}{7}\)
Here, \(\frac{11}{14}\) is more than \(\frac{1}{2}\) and \(\frac{7}{20}\) is less than \(\frac{1}{2}\). So, \(\frac{11}{14}>\frac{7}{20}\).
Here, \(\frac{5}{7}\) is more than \(\frac{1}{2}\) and \(\frac{3}{9}\) is less than \(\frac{1}{2}\). So, \(\frac{5}{7}>\frac{3}{9}\).
Here, \(\frac{6}{7}\) is more than \(\frac{1}{2}\) and \(\frac{4}{10}\) is less than \(\frac{1}{2}\). So, \(\frac{6}{7}>\frac{4}{10}\).
Here, \(\frac{9}{17}\) is more than \(\frac{1}{2}\) and \(\frac{3}{15}\) is less than \(\frac{1}{2}\). So, \(\frac{9}{17}>\frac{3}{15}\).
Here, \(\frac{7}{12}\) is more than \(\frac{1}{2}\) and \(\frac{3}{11}\) is less than \(\frac{1}{2}\). So, \(\frac{7}{12}>\frac{3}{11}\).
Here, \(\frac{1}{3}\) is more than \(\frac{1}{2}\) and \(\frac{5}{9}\) is less than \(\frac{1}{2}\). So, \(\frac{1}{3}<\frac{5}{9}\).
Here, \(\frac{3}{9}\) is more than \(\frac{1}{2}\) and \(\frac{4}{7}\) is less than \(\frac{1}{2}\). So, \(\frac{3}{9}<\frac{4}{7}\).
Try this:
If the length of an ant is \(\frac{1}{4}\) cm—then what is the total length of 16 such ants walking in a line? Use the number line given below.
Solution:
Since the length of an ant is \(\frac{1}{4}\) cm
= \(\frac{16}{4}\) cm
= 4 cm
Therefore, total length of 16 such ants = 4 cm