CBSE Class 6 Mathematics Question 34 of 42

Number Play — Question 37

Back to all questions
37
Question
How many rounds does your year of birth take to reacall the Kaprekar constant?
Answer

If your year of birth is 2000
Step 1: Now from digits of number 2000
Here largest number = 2000
and smallest number = 0002
Let’s subtract them = 2000 – 0002 = 1998
Step 2: Now from digits of number 1998
Here largest number = 9981
and smallest number = 1899
Let’s subtract them = 9981 – 1899 = 8082
Step 3: Now from digits of number 8082
Here largest number = 8820
and smallest number = 0288
Let’s subtract them = 8820 – 0288 = 8532
Step 4: Now from digits of number 8532
Here largest number = 8532
and smallest number = 2358
Let’s subtract them = 8532 – 2358 = 6174
which is a Kaprekar constant.
Hence it took 4 rounds to reach the Kaprekar constant from 2000.