CBSE Class 6 Mathematics Question 22 of 42

Number Play — Question 24

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24
Question
Pratibha uses the digits ‘4‘7’, ‘3’and ‘2’ and makes the smallest and largest 4-digit numbers with them: 2347 and 7432. The difference between these two numbers is 7432 – 2347 = 5085. The sum of these two numbers is 9779. Choose 4-digits to make: (a) the difference between the largest and smallest numbers greater than 508$. (b) the difference between the largest and smallest numbers less than 5085. (e) the sum of the largest and smallest numbers greater than 9779. (d) the sum of the largest and
Answer

(a) Digits – 8, 7, 3 and 2
Largest Number – 8 7 3 2
Smallest Number – 2 3 7 8
Difference = 6 3 5 4
6354 > 5085
(b) Digits – 1, 2, 3 and 4
Largest Number – 4 3 2 1
Smallest Number – 1 2 3 4
Difference = 3 0 8 7
3087 < 5085
(c) Digits – 9, 8, 7 and 6
Largest Number – 9 8 7 6
Smallest Number – 6 7 8 9
Sum = 166 6 5
16665 > 9779
(d) Digits – 1, 2, 3 and 8
Largest Number 8 3 2 1
Smallest Number 1 2 3 8
Sum = 9 5 5 9
9559 < 9779