CBSE Class 7 Mathematics
Question 5 of 11
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Question The thickness of a rupee coin is 1.45 mm. What is the total height of the cylinder formed by placing 36 rupee coins one over the other? Write the answer in centimetres.
Thickness of 1 coin = 1.45 mm Total thickness of 36 coins = 36 × 1.45 = \(\frac{36 \times 145}{100}\) = \(\frac {5220}{100}\) = 52.2 mm Now 10 mm = 1 cm 1 mm = \(\frac {1}{10}\) cm ∴ 52.2 mm = \(\frac {52.2}{10}\) = 5.22 cm.