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Question Given 28p – 36 = 98, find the value of 14p – 19 and 28p – 38.
28p – 36 = 98 ⇒ 28p = 98 + 36 ⇒ 28p = 134 ⇒ p = \(\frac {134}{28}\) ⇒ p = \(\frac {67}{14}\) Now to find the value of (i) 14p – 19 = 14 × \(\frac {67}{14}\) – 19 = 67 – 19 = 48 (ii) 28p – 38 = 28 × \(\frac {67}{14}\) – 38 = 134 – 38 = 96