6
Question Tathagat has written several numbers that leave a remainder of 2 when divided by 6. He claims, “If you add any three such numbers, the sum will always be a multiple of 6.” Is Tathagat’s claim true?
The expression has been written by Tathagat = 6k + 2 where, k = 1, 2, 3, 4, 5, 6,… 6 × 1 + 2 = 8 6 × 2 + 2 = 14 6 × 3 + 2 = 20 6 × 4 + 2 = 26 The sum of three numbers 8 + 14 + 20 = 42, it is a multiple of 6. 14 + 20 + 26 = 60, it is a multiple of 6. Yes, Tathagat’s claim is true.