CBSE Class 8 Mathematics
Question 3 of 12
Proportional Reasoning 2 — Question 3
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Question I have 100 coins in the ratio — no. of ₹ 10 coins : no. of ₹ 5 coins : no. of ₹ 2 coins : no. of ₹ 1 coins :: 4 : 3 : 2 : 1. How much money do I have in coins?
Given no. of ₹ 10 coins : no. of ₹ 5 coins : no. of ₹ 2 coins : no. of ₹ 1 coins :: 4 : 3 : 2 : 1. Total number of coins = 100 Total number of ratio parts = 4 + 3 + 2 + 1 = 10 no. of ₹ 10 coins = \(\frac {4}{10}\) × 100 = 40 no. of ₹ 5 coins = \(\frac {3}{10}\) × 100 = 30 no. of ₹ 2 coins = \(\frac {3}{10}\) × 100 = 30 no. of ₹ 1 coins = \(\frac {1}{10}\) × 100 = 10 Total money = 40 × 10 + 30 × 5 + 2 × 20 + 1 × 10 = 400 + 150 + 40 + 10 = ₹ 600