Construct a square whose area is equal to the difference of the areas of squares of side lengths 5 units and 7 units.

Question

Bright Tutorials · Accepted Answer

Area of square = 7
2
– 5
2
= 49 – 25
= 24 sq. units
1. Construct a square ABCD with a side of 2 cm.
Then DB = 2√2 units
2. Draw BE ⊥ DB at B such that BE = 4 units
3. Join DE.
DE
2
= (2√2)
2
+ 4
2
= 8 + 16
= 24
⇒ DE = √24
4. Draw a square with side DE (DEFG).
Area of DEFG = (√24)
2
= 24 square units.

The Baudhayana-Pythagoras Theorem — Question 7