Let, there be two circles with center P and X with equal radius.

From figure,
QR and YZ are equal chords.
In ∆ PQR and ∆ XYZ,
⇒ PQ = XY (Radius of congruent circles)
⇒ PR = XZ (Radius of congruent circles)
⇒ QR = YZ (Chords are equal)
∴ ∆ PQR ≅ ∆ XYZ (By S.S.S. congruence rule)
We know that,
Corresponding parts of congruent triangles are equal.
⇒ ∠QPR = ∠YXZ (By C.P.C.T.)
Hence, proved that equal chords of congruent circles subtend equal angles at their centers.