Let ABCD be the cyclic parallelogram.

We know that opposite angles of a parallelogram are equal.
⇒ ∠A = ∠C .......(1)
⇒ ∠B = ∠D .......(2)
We know that the sum of opposite angles of a cyclic quadrilateral is 180°.
⇒ ∠A + ∠C = 180°
⇒ ∠A + ∠A = 180° (From equation (1))
⇒ 2∠A = 180°
⇒ ∠A =
⇒ ∠A = 90°.
We know that,
If one angle of a parallelogram is 90°, then it is a rectangle.
Thus, quadrilateral ABCD is a rectangle.
Hence, proved that a cyclic parallelogram is a rectangle.