Draw a perpendicular from the center of the circle to the line AD, such that OM ⊥ AD
BC and AD are the chords of smaller circle and the bigger circle respectively.

We know that,
Perpendicular from the center bisects the chord.
⇒ BM = MC ......... (1)
⇒ AM = MD ......... (2)
By subtracting equation (1) from (2), we get :
⇒ AM − BM = MD − MC
⇒ AB = CD
Hence, proved that AB = CD.
BRIGHT TUTORIALS
BRIGHT TUTORIALS
CBSE Class IX | Academic Year 2026-2027
9403781999
Excellence in Education
Mathematics | CirclesWeb Content • Interactive Notes
Circles — Interactive Study Guide
Circle Theorems Quick Reference
- Equal chords ⇔ equal central angles
- Perpendicular from centre bisects the chord
- Equal chords ⇔ equidistant from centre
- Central angle = 2 × inscribed angle (same arc)
- Angles in same segment are equal
- Angle in semicircle = 90°
- Opposite angles of cyclic quad = 180°
Problem-Solving Toolkit
For chord problems: Drop perpendicular from centre → bisects chord → use Pythagoras.
For angle problems: Identify if angle is at centre or circumference → apply the 2x rule.
For cyclic quad: Opposite angles add up to 180°.
Quick Self-Check
- Inscribed angle = 35°. Central angle for the same arc? (70°)
- Chord = 10 cm, distance from centre = 12 cm. Radius? (√(25+144) = √169 = 13 cm)
- ABCD is cyclic, ∠A = 95°. Find ∠C. (85°)
