CBSE Class 9 Mathematics Question 6 of 6

Heron's Formula — Question 6

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Question 6

An isosceles triangle has perimeter 30 cm and each of the equal sides is 12 cm. Find the area of the triangle.

Answer

Length of equal sides (a and b) = 12 cm

Let third side of triangle (c) = x cm

Given,

Perimeter of triangle = 30

∴ 12 + 12 + x = 30

⇒ 24 + x = 30

⇒ x = 30 - 24

⇒ x = 6 cm.

∴ c = 6 cm.

By formula,

Semi perimeter (s) = Perimeter of triangle2=302\dfrac{\text{Perimeter of triangle}}{2} = \dfrac{30}{2} = 15 cm.

By Heron's formula,

Area of triangle (A) = s(sa)(sb)(sc)\sqrt{s(s - a)(s - b)(s - c)} sq.units

Substituting values we get :

A=15(1512)(1512)(156)=15×3×3×9=1215=915 cm2.A = \sqrt{15(15 - 12)(15 - 12)(15 - 6)} \\[1em] = \sqrt{15 \times 3 \times 3 \times 9} \\[1em] = \sqrt{1215} \\[1em] = 9\sqrt{15} \text{ cm}^2.

Hence, area of triangle = 9159\sqrt{15} cm2.