Linear Equations in Two Variables — Question 4

Given, equation :

⇒ x = 4y

Substituting x = 0, in the given equation, we get :

⇒ 0 = 4y

⇒ y = $\dfrac{0}{4}$

⇒ y = 0

∴ Solution is (0, 0).

Substituting x = 1, in the given equation, we get :

⇒ 1 = 4y

⇒ y = $\dfrac{1}{4}$.

∴ Solution is $\Big(1, \dfrac{1}{4}\Big)$.

Substituting x = 4, in the given equation, we get :

⇒ 4 = 4y

⇒ y = $\dfrac{4}{4}$

⇒ y = 1

∴ Solution is (4, 1).

Substituting x = -4, in the given equation, we get :

⇒ -4 = 4y

⇒ y = $\dfrac{-4}{4}$

⇒ y = -1

∴ Solution is (-4, -1).

Hence, solutions for equation x = 4y are (0, 0), $(1, \dfrac{1}{4}\Big)$, (4, 1) and (-4, -1).