CBSE Class 9 Mathematics
Question 5 of 15
Linear Equations in Two Variables — Question 5
Back to all questionsGiven,
⇒ x = 3y
On re-arranging the equation, we have :
⇒ x - 3y = 0
⇒ (1)x + (-3)y + (0) = 0
Comparing above equation with ax + by + c = 0, we get :
a = 1, b = -3 and c = 0
Hence, linear equation : 1x - 3y + 0 = 0, a = 1, b = -3 and c = 0.