We know that,
Sum of all angles round a point is equal to 360°.
⇒ x + y + w + z = 360°
⇒ (x + y) + (w + z) = 360°
As,
x + y = w + z
⇒ (x + y) + (x + y) = 360°
⇒ 2(x + y) = 360°
⇒ (x + y) = = 180°.
⇒ x + y = 180° and w + z = 180°.
Since the sum of adjacent angles, x and y with OA and OB as the non-common arms is 180° we can say that AOB is a straight line.
Hence, proved that AOB is a straight line.
BRIGHT TUTORIALS
BRIGHT TUTORIALS
CBSE Class IX | Academic Year 2026-2027
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Mathematics | Lines and AnglesWeb Content • Interactive Notes
Lines and Angles — Interactive Study Guide
Angle Pair Cheat Sheet
| Pair | Relationship | Condition |
|---|---|---|
| Complementary | Sum = 90° | Any two angles |
| Supplementary | Sum = 180° | Any two angles |
| Linear Pair | Sum = 180° | Adjacent + on a line |
| Vertically Opposite | Equal | Intersecting lines |
| Corresponding | Equal | Parallel lines + transversal |
| Alternate Interior | Equal | Parallel lines + transversal |
| Co-interior | Sum = 180° | Parallel lines + transversal |
Triangle Angle Facts
∠A + ∠B + ∠C = 180° (angle sum property)
Exterior angle = sum of remote interior angles
Quick Self-Check
- Two parallel lines cut by a transversal: one angle is 72°. Find all 8 angles. (72°, 108° alternating)
- In ΔABC, ∠A = 45°, ∠B = 65°. Find ∠C. (70°)
- An exterior angle of a triangle is 130°. One non-adjacent interior angle is 50°. Find the other. (80°)
