CBSE Class 9 Mathematics Question 8 of 9

Statistics — Question 8

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Question 8

A random survey of the number of children of various age groups playing in a park was found as follows:

Age (in years)Number of children
1 - 25
2 - 33
3 - 56
5 - 712
7 - 109
10 - 1510
15 - 174

Draw a histogram to represent the data above.

Answer

From the given data, we can observe that the class intervals have varying widths. The areas of the rectangles should be proportional to the frequencies in a histogram.

For example, when the class size is 5, the length of the rectangle is 10. So when the class size is 1, the length of the rectangle will be 10/5 × 1 = 2

Age (in years)Number of childrenWidth of classLength of rectangle
1 - 251(5 x 1)/1 = 5
2 - 331(3 x 1)/1 = 3
3 - 562(6 x 1)/2 = 3
5 - 7122(12 x 1)/2 = 6
7 - 1093(9 x 1)/3 = 3
10 - 15105(10 x 1)/5 = 2
15 - 1742(4 x 1)/2 = 2

Steps of construction :

  1. Take the age of children on x-axis, using scale 1 unit = 1 year.

  2. Take proportion of children per 1 year interval on y-axis, using scale 1 unit = 1 child.

  3. To represent our first Head, i.e., (1 - 2) we draw a rectangular bar with width 1 unit and length 5 units.

  4. Similarly, other Heads are represented without leaving a gap between two consecutive bars, according to the table.

A random survey of the number of children of various age groups playing in a park was found as follows: NCERT Class 9 Mathematics CBSE Solutions.
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Statistics — Interactive Study Guide

Histogram vs Bar Graph

FeatureBar GraphHistogram
Data typeDiscrete/categoricalContinuous/grouped
GapsYes (between bars)No (bars touch)
Unequal widthsNot applicableUse frequency density

Mean, Median, Mode

Mean: Sum of all values / count. Affected by extreme values.
Median: Middle value (after sorting). Not affected by extreme values.
Mode: Most frequent value. Can have multiple modes or no mode.

Quick Self-Check

  1. Mean of 2, 4, 6, 8, 10? (30/5 = 6)
  2. Median of 3, 1, 7, 5, 9? (Sorted: 1,3,5,7,9. Median = 5)
  3. Mode of 2, 3, 3, 5, 5, 5, 7? (5)

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