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Surface Areas and Volumes — Question 13

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Question 9

A right circular cylinder just encloses a sphere of radius r. Find

(i) surface area of the sphere,

(ii) curved surface area of the cylinder,

(iii) ratio of the areas obtained in (i) and (ii).

A right circular cylinder just encloses a sphere of radius r. NCERT Class 9 Mathematics CBSE Solutions.
Answer

From figure,

Radius of cylinder = radius of sphere = r

Height of cylinder = Diameter of sphere = 2r

(i) By formula,

Surface area of sphere = 4πr2

Hence, surface area of sphere = 4πr2.

(ii) By formula,

Curved surface area of cylinder = 2πrh

= 2πr × 2r

= 4πr2.

Hence, curved surface area of cylinder = 4πr2.

(iii) Ratio = Surface area of sphereC.S.A. of cylinder=4πr24πr2=11\dfrac{\text{Surface area of sphere}}{\text{C.S.A. of cylinder}} = \dfrac{4πr^2}{4πr^2} = \dfrac{1}{1}.

Hence, the ratio between these two surface area is 1 : 1.

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Surface Areas and Volumes — Interactive Study Guide

Formula Master Table

SolidCSATSAVolume
Cube (a)4a²6a²
Cuboid (l,b,h)2h(l+b)2(lb+bh+hl)lbh
Cylinder (r,h)2πrh2πr(r+h)πr²h
Cone (r,h,l)πrlπr(l+r)⅓πr²h
Sphere (r)4πr²&frac43;πr³
Hemisphere (r)2πr²3πr²⅔πr³

Common Traps

Cone CSA uses slant height l, NOT height h! l = √(r²+h²)
Hemisphere TSA = CSA + base circle = 2πr² + πr² = 3πr²
Use radius, not diameter! If diameter is given, divide by 2 first.

Quick Self-Check

  1. Volume of cube with side 5 cm? (125 cm³)
  2. CSA of cylinder with r=7, h=10? (2×22/7×7×10 = 440 cm²)
  3. Volume of cone with r=3, h=4? (⅓×π×9×4 = 12π cm³)

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