Given :
AC = AD
AB bisects ∠A i.e, ∠CAB = ∠DAB
In Δ ABC and Δ ABD
⇒ AB = AB (Common side)
⇒ ∠CAB = ∠DAB (Proved above)
⇒ AC = AD (Given)
∴ Δ ABC ≅ Δ ABD (By S.A.S. Congruence rule)
⇒ BC = BD (By C.P.C.T.)
Hence, BC and BD are of equal length.
Given :
AC = AD
AB bisects ∠A i.e, ∠CAB = ∠DAB
In Δ ABC and Δ ABD
⇒ AB = AB (Common side)
⇒ ∠CAB = ∠DAB (Proved above)
⇒ AC = AD (Given)
∴ Δ ABC ≅ Δ ABD (By S.A.S. Congruence rule)
⇒ BC = BD (By C.P.C.T.)
Hence, BC and BD are of equal length.