Given :
⇒ AD = BC
From figure,
⇒ AD ⊥ AB, ∠OAD = 90°
⇒ BC ⊥ AB, ∠OBC = 90°
In △ BOC and △ AOD,
⇒ ∠BOC = ∠AOD (Vertically opposite angles are equal)
⇒ ∠OBC = ∠OAD (Each equal to 90°)
⇒ BC = AD (Given)
∴ △ BOC ≅ △ AOD (By A.A.S. congruence rule)
We know that,
Corresponding parts of congruent triangles are equal.
∴ BO = AO (By C.P.C.T.)
Hence, proved that CD bisects AB and O is the mid-point of AB.
