Given :
AB = PQ, BC = QR = x (let) and AM = PN.
(i) Given,
AM is the median of △ ABC
∴ BM = CM = .....(1)
Also, PN is the median of △ PQR
∴ QN = RN = ......(2)
From equation (1) and (2), we get :
BM = QN ..........(3)
Now, in △ ABM and △ PQN we have,
⇒ AB = PQ (Given)
⇒ BM = QN [From equation (3)]
⇒ AM = PN (Given)
∴ △ ABM ≅ △ PQN (By S.S.S. congruence rule)
Hence, proved that △ ABM ≅ △ PQN.
(ii) Since,
△ ABM ≅ △ PQN
We know that,
Corresponding parts of the congruent triangle are equal.
∠B = ∠Q (By C.P.C.T.) ...........(4)
Now, In △ ABC and △ PQR we have
⇒ AB = PQ (Given)
⇒ ∠B = ∠Q [From equation (4)]
⇒ BC = QR (Given)
∴ △ ABC ≅ △ PQR (By S.A.S. congruence rule)
Hence, proved that △ ABC ≅ △ PQR.

