Given :
ABC and DBC are isosceles triangles.
Join AD.

In △ DAB and △ DAC,
⇒ AB = AC (Given)
⇒ BD = CD (Given)
⇒ AD = AD (Common side)
∴ △ ABD ≅ △ ACD (By S.S.S. congruence rule)
We know that,
Corresponding sides of congruent triangles are equal.
∴ ∠ABD = ∠ACD (By C.P.C.T.)
Hence, proved that ∠ABD = ∠ACD.
