14
Question Question 14
A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity just before touching the ground.
Given,
Initial velocity (u) = 0
Tower height = total distance = 19.6 m
g = 9.8 ms-2
Final velocity (v) = ?
According to the third equation of motion,
v2 = 2gs + u2
Substituting we get,
v2 = (2 x 9.8 x 19.6) + 0
v =
v = 19.6 ms-1
Hence, final velocity = 19.6 ms-1