CBSE Class 9 Science Question 22 of 22

Gravitation — Question 2

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Question 2

Why is the weight of an object on the moon 16\dfrac{1}{6}th its weight on the earth?

Answer

The moon's gravitation force is determined by the mass and the size of the moon.

The mass of moon is 1100\dfrac{1}{100} times and its radius 14\dfrac{1}{4} times that of earth. As a result, the gravitational attraction on the moon is about one sixth when compared to earth. Hence, the weight of an object on the moon is 16\dfrac{1}{6}th its weight on the earth.

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Science | Chapter 9: GravitationWeb Content — Quick Reference

Chapter 9: Gravitation — Quick Reference

universal law gravity mass weight pressure buoyancy Archimedes principle relative density

Quick Revision Points

  • F = Gm₁m₂/r² (G = 6.674 × 10⁻¹¹ N·m²/kg²)
  • g = GM/R² = 9.8 m/s² (Earth); g on Moon ≈ g/6
  • Mass (kg, constant) vs Weight (N = mg, varies with location)
  • Pressure P = F/A (Pa = N/m²); Fluid pressure P = hρg
  • Archimedes: buoyant force = weight of displaced fluid
  • Float if density < fluid density; Sink if density > fluid density
  • Relative density = density of substance / density of water (no unit)
Exam Tips for Chapter 9
  • Read the detailed chapter notes for complete coverage of all NCERT topics.
  • Practice all NCERT in-text and back exercise questions — they are frequently asked in exams.
  • Focus on comparison tables, diagrams, and definitions — these are high-scoring areas.
  • For numericals (if applicable), practice at least 20 problems of varying difficulty.
  • Refer to the practice question bank (200+ questions) for thorough preparation.
Related Resources
  • Detailed Notes: ch09-gravitation.html
  • Practice Questions: 100+ questions with answers in 05-practice-questions/
  • Chapter Test: 30-mark test paper in 06-tests/chapter-tests-30marks/
  • Formula Sheet: Complete formula reference in 03-teacher-aid/formula-sheet.html