Given,

Diameter of track (d) = 200 m

Circumference of the track = πd = 200π m

So, distance covered in 40 seconds = 200π m

Distance covered in 1 sec = $\dfrac{200π}{40}$

Distance covered in 2 min 20 sec (i.e., 60 + 60 + 20 = 140 sec) = $\dfrac{200π}{40}$ x 140

= $\dfrac{200 \times 22 \times 140}{7 \times 40}$

= 2200 m

Number of rounds completed in 140 sec = $\dfrac{140}{40}$ = 3.5

∴ the final position (with respect to the initial position) is at the opposite end of the circular track. So, the net displacement will be equal to the diameter of the track = 200 m.

Hence, the net distance covered by the athlete is 2200 m and the total displacement of the athlete is 200 m.

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