Motion — Question 10

Given,

Radius of the orbit (r) = 42250 km

∴ circumference of the orbit

= 2 x $\dfrac{22}{7}$ x r

= 2 x $\dfrac{22}{7}$ x 42250

= 265571.42 km

Time taken to complete one revolution in the orbit = 24 hours

Convert hours into sec

1 hour = 3600 sec

So, 24 hour = 24 x 3600 sec

Speed = $\dfrac{\text{Distance}}{\text{Time}}$

Substituting we get,

Speed = $\dfrac{265571.42}{24 \times 3600}$ = 3.07 kms^-1

∴ Speed of the artificial satellite = 3.07 kms^-1.