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ICSE Class 10 Chemistry Question 22 of 28

Acids, Bases and Salts — Question 15

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Question

Question 14

You are provided with the following chemicals:

NaOH, Na2CO3, H2O, Zn(OH)2, CO2, HCl, Fe, H2SO4, Cl2, Zn.

Using the suitable chemicals from the given list only, state briefly how you would prepare :

(a) iron (III) chloride

(b) sodium sulphate

(c) sodium zincate

(d) iron (II) sulphate

(e) sodium chloride

Answer

(a) Iron (III) Chloride: By synthesis i.e., direct combination of elements.
2Fe + 3Cl2 ⟶ 2FeCl2

(b) Sodium sulphate: By neutralisation of an alkali (caustic soda) with acid (dilute sulphuric acid)
2NaOH + H2SO4 ⟶ Na2SO4 + 2H2O

(c) Sodium zincate: By the action of metals with alkalis
Zn + 2NaOH ⟶ Na2ZnO2 + H2

(d) Iron (II) sulphate: Method of Simple Displacement by the action of dilute acid (H2SO4) on an active metal (iron).
Fe + H2SO4 (dil.) ⟶ FeSO4 + H2

(e) Sodium chloride: By the neutralisation reaction of strong acid (HCl) with strong base (NaOH) also known as titration NaOH + HCl ⟶ NaCl + H2O