ICSE Class 10 Chemistry Question 10 of 10

Analytical Chemistry — Question 8

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Question

Question 8

Write balanced equation:

(a) Reaction of sodium hydroxide solution with Iron (III) chloride solution

(b) Copper sulphate solution with ammonium hydroxide solution

Answer

(a) When sodium hydroxide solution is added to FeCl3 dropwise, a reddish brown ppt is obtained, which is insoluble in excess of NaOH:

FeCl3Yellow+3NaOHColourlessFe(OH)3Reddish brown ppt+3NaClColourless\underset{\text{Yellow}}{{\text{FeCl}_3}} + \underset{\text{Colourless}}{3\text{NaOH}} \longrightarrow \underset{\text{Reddish brown ppt}}{\text{Fe(OH)}_3↓} + \underset{\text{Colourless}}{3\text{NaCl}}

(b) When ammonia solution is added dropwise to cupper sulphate, a pale blue ppt of copper hydroxide is obtained.

CuSO4Blue+2NH4OHCu(OH)2Pale Blue ppt+(NH4)2SO4Colourless in solution\underset{\text{Blue}}{{\text{CuSO}_4}} + 2\text{NH}_4\text{OH} \longrightarrow \underset{\text{Pale Blue ppt}}{\text{Cu(OH)}_2} ↓ + \underset{\text{Colourless in solution}}{(\text{NH}_4)_2\text{SO}_4}

On adding excess of ammonia solution, the ppt dissolves and a deep blue solution is obtained.

Cu(OH)2+(NH4)2SO4+2NH4OH[(Cu(NH3)4]SO4Tetraammine copper (II) sulphate+4H2O\text{Cu(OH)}_2 + (\text{NH}_4)_2\text{SO}_4 + 2\text{NH}_4\text{OH} \longrightarrow \underset{\text{Tetraammine copper (II) sulphate}}{[(\text{Cu(NH}_3)_4]\text{SO}_4} + 4\text{H}_2\text{O}