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ICSE Class 10 Chemistry Question 21 of 25

Gay Lussac's Law — Avogadro's Law — Mole Concept — Question 21

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Question

Question 21

Calculate the number of moles of KClO3 that will be required to give 6 moles of oxygen.

Answer

2KClO3 ⟶ 2KCl + 3O2

O2:KClO33:26:x\begin{matrix} \text{O}_2 & : & \text{KClO}_3 & \\ 3 & : & 2 \\ 6 & : & x \end{matrix}

23×6=x⇒x=4 moles\dfrac{2}{3} \times 6 = x \\[0.5em] \Rightarrow x = 4 \text{ moles}

Hence, 4 moles of KClO3 are required to give 6 moles of oxygen.