Gay Lussac's Law — Avogadro's Law — Mole Concept — Question 23

Gram molecular mass of N₂O
= (2 x 14) + 16
= 44 g

44 g of N₂O = 1 mole

∴ 5 g of N₂O = $\dfrac{1}{44} \times 5 = 0.11$ moles

Gram molecular mass of NO

= 14 + 16
= 30 g

30 g of NO = 1 mole

∴ 5 g of NO = $\dfrac{1}{30} \times 5 = 0.16$ moles

Hence, 5 g. of NO has higher moles than 5 g. of N₂O