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ICSE Class 10 Chemistry Question 8 of 25

Gay Lussac's Law — Avogadro's Law — Mole Concept — Question 8

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Question 8

100 cc. each of water gas and oxygen are ignited and the resultant mixture of gases cooled to room temp. Calculate the composition of the resultant mixture. [Water gas contains CO and H2 in equal ratio]

Answer

Given,

Vol of CO = 50 cc and H2 = 50 cc [As Water gas contains CO and H2 in equal ratio] and O2 = 100 cc

[By Lussac's law]

CO1 vol.+:H21 vol.+:O21 vol.⟶CO21 vol +: H2O1 vol\underset{\text{\scriptsize{1 vol.}}}{\text{\scriptsize{CO}}} \underset{:}{\text{\scriptsize{+}}} \underset{\text{\scriptsize{1 vol.}}}{\text{\scriptsize{H}}_2} \underset{:}{\text{\scriptsize{+}}} \underset{\text{\scriptsize{1 vol.}}}{\text{\scriptsize{O}}_2} \longrightarrow \underset{\text{\scriptsize{1 vol}}}{\text{\scriptsize{CO}}_2} \underset{:}{\text{\scriptsize{ +}}} \underset{\text{\scriptsize{1 vol}}}{\text{\scriptsize{ H}}_2 \text{\scriptsize{O}}}

To calculate the amount of O2 used,

CO:O21 vol.:1 vol.50 cc:x cc\begin{matrix} \text{CO}& : & \text{O}_2 & \\ 1 \text{ vol.} & : & 1 \text{ vol.} & \\ 50 \text{ cc} & : & x \text{ cc} & \\ \end{matrix}

As ratio between CO and O2 is same so, O2 used is 50 cc.

Hence, remaining O2 = 100 - 50 = 50 cc.

To calculate the amount of CO2 produced,

CO:CO21 vol.:1 vol.50 cc:y cc\begin{matrix} \text{CO}& : & \text{CO}_2 & \\ 1 \text{ vol.} & : & 1 \text{ vol.} & \\ 50 \text{ cc} & : & y \text{ cc} & \\ \end{matrix}

1 vol of CO produces 1 vol. of CO2
Hence, CO2 produced = 50 cc.

Therefore, the resultant mixture has 50 cc of O2 + 50 cc of CO2