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ICSE Class 10 Chemistry Question 14 of 64

Metallurgy — Question 14

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Question

Question 14

Give equations for the reduction of :

(a) Iron (II) oxide

(b) Iron (III) oxide

(c) Lead (II) oxide

(d) Zinc oxide

Answer

(a) Reduction of Iron (II) oxide

FeO+C→ΔFe+CO\text{FeO} + \text{C} \xrightarrow{\Delta} \text{Fe} + \text{CO}

FeO+CO→ΔFe+CO2\text{FeO} + \text{CO} \xrightarrow{\Delta} \text{Fe} + \text{CO}_2

FeO+H<em>2→ΔFe+H</em>2O{\text{FeO}} + \text{H}<em>2 \xrightarrow{\Delta} {\text{Fe}} + \text{H}</em>{2}\text{{O}}

(b) Reduction of Iron (III) oxide

Fe2O3+2Al→2Fe+Al2O3+heat\text{Fe}_2\text{O}_3 + 2\text{Al} \rightarrow \text{2Fe} + \text{Al}_2\text{O}_3 + \text{heat}

(c) Reduction of Lead (II) oxide

PbO+C→ΔPb+CO\text{PbO} + \text{C} \xrightarrow{\Delta} \text{Pb} + \text{CO}

PbO+CO→ΔPb+CO2\text{PbO} + \text{CO} \xrightarrow{\Delta} \text{Pb} + \text{CO}_2

PbOyellow+H<em>2→ΔPbgreenish white+H</em>2O\underset{\text{yellow}}{\text{PbO}} + \text{H}<em>2 \xrightarrow{\Delta} \underset{\text{greenish white}}{\text{Pb}} + \text{H}</em>{2}\text{{O}}

(d) Reduction of Zinc oxide

ZnO+C→1400°CZn+CO\text{ZnO} + \text{C} \xrightarrow{1400\degree \text{C}} \text{Zn} + \text{CO}